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Kinetics Kinetics

Kinetics - PowerPoint Presentation

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Kinetics - PPT Presentation

Chemistry 1106 Introduction Kinetics Reaction Rates in any Chemical reaction Dependent Temperature T Arrhenius eq Concentration Catalysts if any Activation energy may otherwise be denoted as the minimum energy necessary for a specific chemical reaction to occur ID: 613267

reaction logb slope rulelogb logb reaction rulelogb slope rate logarithm information logc energy kinetics experiment temperature constant base solution

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Slide1

Kinetics

Chemistry 1106Slide2

Introduction

Kinetics

Reaction Rates in any Chemical reaction

Dependent

Temperature [T] (Arrhenius eq.)

Concentration

Catalysts (if any)

Activation energy

may otherwise be denoted as the minimum energy necessary for a specific chemical reaction to occur Slide3

information

Rate=k

T

[A]

x

[B]y where x and y are the order of the reaction and kT is a rate constant dependent on the Temperature. Slide4

Reaction energy diagramSlide5
Slide6

Information for todays RXN

Colored solution KMnO

4

is purple and reacts with oxalic acid to produce a colorless

solution

We will monitor the disappearance of the color Y

ou can follow the disappearance or the appearance of color over time to determine that a reaction has occurredMust work fast to get good results(%Absorbance ) in the Kinetics programFirst order at 525 nm

Add KMnO4 at the endSlide7

Calculations

2KMnO

4

+ 5H

2

C

2

O

4

+H

2

0+ MnSO

4

→Mn

+2

+ CO2+OPRate =kT [A]x[B]y where A = KMnO4 B= H2C2O4 MnSO4 this is the catalyst and thus remains constant and can be ignored Water is a solvent kT = since the temperature constant, we can neglect for now

Information for todays RXNSlide8

Experiment

Exp

#

H2O

H2C2O4

MnSO4

KMnO4

Rate

**1**

10

5

1

1

2

5

10

1

1

3

9512

**Because 1 will be your control value it is the one you use as a “control”

*** The values is how much of the substance (in mL) in that experiment you will mix.Slide9

Report

Remember to read the blank (water)

The slope = rate

Change graph title

Print all graphs

YOU NEED THE RATE OR SLOPE OF THE REACTION in Absorbance

Final NotesSlide10

Data table to calculate

Using the slope you get from the graphs

Where R1 is experiment 1 and R2 is

exp

2

R2= [ 3]

x [20]y then R2 /R1 =2y R1= [3]x [10]y

solving for y

=log

(slope of R2/slope R1)

log 2

Repeat

R3/R1

Etc

– Slide11

Rule name

Rule

Logarithm product rule

log

b

(

x ∙ y) = log

b

(

x

)

 + 

log

b

(

y

)Logarithm quotient rulelogb(x / y) = logb(x) - logb(y)Logarithm power rulelogb(x y) = y ∙ logb(x)Logarithm base switch rulelogb(c

) = 1 / log

c

(b)Logarithm base change rulelogb(x) = logc(x) / logc(b)Derivative of logarithmf (x) = logb(x) ⇒ f ' (x) = 1 / ( x ln(b) )Integral of logarithm∫ logb(x) dx = x ∙ ( logb(x) - 1 / ln(b) ) + CLogarithm of 0logb(0) is undefinedLogarithm of 1logb(1) = 0Logarithm of the baselogb(b) = 1Logarithm of infinitylim logb(∞) = ∞, when x→∞