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Tension Problems Tension Problems

Tension Problems - PowerPoint Presentation

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Tension Problems - PPT Presentation

How To Solve Tension Problems F ollow the same procedure as other force problems but keep in mind 1 Draw a free body diagram for EACH object or for each junction in a rope How To Solve Tension Problems ID: 216086

blocks tension magnitude block tension blocks block magnitude acceleration force connected practice rope string pulley find shown equation equal

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Slide1

Tension ProblemsSlide2

How To Solve Tension Problems

F

ollow the same procedure as other force problems, but keep in mind:

1) Draw a free body diagram for EACH object or for each junction in a rope.Slide3

How To Solve Tension Problems

F

ollow the same procedure as other force problems, but keep in mind:

1) Draw a free body diagram for EACH object or for each junction in a rope.

2) Remember that the tension on opposite sides of a rope is equal and opposite.Slide4

How To Solve Tension Problems

F

ollow the same procedure as other force problems, but keep in mind:

1) Draw a free body diagram for EACH object or for each junction in a rope.

2) Remember that the tension on opposite sides of a rope is equal and opposite.3) Create a system of equations – write force equations for each object / rope and set them equal to each other.Slide5

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We DoSlide6

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

FIRST: Think about what is going on in the problem.

What do you know about the system and about how the blocks will move?Slide7

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

There is just one rope, so the tension on each side is equal.The two blocks will have the same acceleration (because they are connected), but the direction of the acceleration will be different.

90g block will move up. 110 g block will move down.

What’s our next step?Slide8

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

Draw free body diagrams for each mass.

What’s next?Slide9

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

Add the forces on each mass, and set = ma.

What’s next?

1

st

Equation

F

net

= ma

T – mg = ma

T –

0.9

= 0.09 a

2

nd

Equation

F

net

= ma

mg

– T= ma

1.1 – T =

0.11aSlide10

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

Set the two Ts equal to each other to solve a.

What’s next?

1

st

Equation

F

net

= ma

T – mg = ma

T – 0.9 = 0.09 a

2

nd

Equation

F

net

= ma

mg

– T= ma

1.1 – T =

0.11a

0.09a + 0.9 = 1.1 – 0.11a

a

= 1

m/s

2Slide11

Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find

a) the magnitude of the acceleration of each block

b) Tension force on the blocks

Tension Practice – We Do

Plug a into either equation to solve T.

1

st

Equation

F

net

= ma

T – mg = ma

T – 0.9 = 0.09 a

2

nd

Equation

F

net

= ma

mg

– T= ma

1.1 – T =

0.11a

0.09a + 0.9 = 1.1 – 0.11a

a

= 1

m/s

2

T = 1.1 – 0.11a = 1.1 – 0.11(1)

T =

0.99 N Slide12

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

FIRST:

Think about what is going on in the problem.

What do you know about the system and about how the blocks will move?Slide13

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

FIRST:

Think about what is going on in the problem.

Tension is equal and opposite because they are connected by the same rope.

Acceleration is the same (b/c connected)

What’s our next step?Slide14

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

Next: Draw free-body diagrams for each object

What’s our next step?Slide15

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

Add up the forces and set = ma

What’s our next step?

1

st

Equation

2

nd

Equation

F

net

=

ma

F

net

=

ma

T =

10a

50

– T = 40a Slide16

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

Set the two T s equal to each other.

What’s our next step?

1

st

Equation

2

nd

Equation

F

net

=

ma

F

net

=

ma

T =

10a

50

– T =

40a

50 – T = 40a

50 – 10a = 40a

Slide17

A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.

 

a) What is the magnitude of the acceleration of the 40-kg block?

b) What is the magnitude of the tension T in the rope that connects the two blocks?

Tension Practice – We Do

Solve for a then solve for t.

1

st

Equation

2

nd

Equation

F

net

=

ma

F

net

=

ma

T =

10a

50

– T =

40a

50 – T = 40a

50 – 10a = 40a

a = 1 m/s

2

T = 10a = 10 NSlide18

Check your understandingSlide19

Check your understanding

Tension is equal in all parts of a rope.Slide20

Find the tension in each cable.

2) Find the tension in each cable and the acceleration of the blocks. M

1

= 10 kg, and M

2 = 5 kgTension Practice – You DoSlide21

Find the tension in each cable.

Tension Practice – You Do

Strategy: Draw the free body diagrams for the weight and for the middle junction. Add the forces and set = 0. (no a). You will find

T

3

= 200N

a

nd

T

1X

+ T

2X

– T

3

= 0

T

1Y

+ T

2Y

– T

3

= 0 (you will need to use trig)

Then, you’ll have to solve for one of the

Ts

and plug into the other equation.

T

1

= 148.4 N

T

2

= 79.0 N

T

3

= 200 NSlide22

2) Find the tension in each cable and the acceleration of the blocks.

Tension Practice – You Do

Strategy: Draw the free body diagrams for

each weight. Add

the forces and set =

ma.

You

will find

M

1

a = T

and

M

2

a = M

2

g - T

Set the

Ts

equal.

T = 30 N

a = 3.3 m/s

2