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Ch. 9 Project: Modeling Aircraft Motion Kaylen  Cruse 4/17/13 Ch. 9 Project: Modeling Aircraft Motion Kaylen  Cruse 4/17/13

Ch. 9 Project: Modeling Aircraft Motion Kaylen Cruse 4/17/13 - PowerPoint Presentation

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Uploaded On 2019-10-31

Ch. 9 Project: Modeling Aircraft Motion Kaylen Cruse 4/17/13 - PPT Presentation

Ch 9 Project Modeling Aircraft Motion Kaylen Cruse 41713 2 nd Blk Qs 14 amp Answers 1 What will happen to the aircraft if the lift is held constant while the weight is decreased say from burning off fuel ID: 761496

lift 205 force weight 205 lift weight force aircraft plane 000 255 amp 2200 happen held constant ground brothers

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Ch. 9 Project: Modeling Aircraft Motion Kaylen Cruse 4/17/13 2 nd Blk.

Q’s 1-4 & Answers 1 . What will happen to the aircraft if the lift is held constant while the weight is decreased (say from burning off fuel)? The airplane will lift higher, go upwards, lift increase 2. What will happen to the aircraft if the lift is decreased while the weight is held constant ? Lift decrease, go downward/lower 3. What will happen to the aircraft if the thrust is increased while the drag is held constant ? Fly faster 4. What will happen to the aircraft if the drag is increased while the thrust is held constant? Fly slower

Q’s 5-7& Answers 5. If 1 kg = 2.205 lb, convert the weight of the Wright brothers’ plane kilograms. 2.205 lb. = 700 lb. 700 lb. = 2.205 lb.(w) w= 700 lb./2.205 lb. w=317.4603175 1 kg w w= about 317.5 kg 6. If acceleration due to gravity is a= 9.80 m/sec², determine the force due to weight on the Wright brothers’ plane . F=ma F=317.5 kg (9.80 m/s²) F=3111.5 N 7. What must be true about the lift force of the Wright brothers’ plane for it to get off the ground ? The lift force has to be 3111.5 or higher for the plane to lift off the ground.

Q. 8 & Answer 8. The weight of a fully loaded Cessna 170B is 2200 lb. What lift force is required to get this plane off the ground ? 2.205 lb./ 1 kg = 2200 lb./ w   2200 lb. = 2.205 lb. (w) w= 2200 lb. / 2.205 lb. w= 997.7324263 kg w= about 997.7 kg   F= ma, F= 997.7 kg (9.80 m/s²), F=9777.777778 N, F= about 9777.8 N  

Q. 9 & Answer 9. The maximum gross weight of a Boeing 747 is 255,000 lb. What lift force is required to get this jet off the ground? 2.205 lb. / 1 kg. = 255,000 lb./ w 255,000 lb. = 2.205 lb. (w) w= 255,000 lb. / 2.205 lb. w= 115646.2585 kg w= about 115646.3 kg   F=ma, F= 115646.3 kg (9.80 m/s²), F=1,133,333.333 N, F= about 1,133,333.3 N

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