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Games: Mixed Strategies - PowerPoint Presentation

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MICROECONOMICS Principles and Analysis Frank Cowell Almost essential Game Theory Strategy and Equilibrium Prerequisites July 2015 1 Introduction Presentation builds on Game Theory Strategy and Equilibrium ID: 550014

july strategy strategies 2015 strategy july 2015 strategies mixed equilibrium game pure probability audit payoff player problem expected taxpayer set plays contribute

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Slide1

Games: Mixed Strategies

MICROECONOMICSPrinciples and Analysis Frank Cowell

Almost essential Game Theory: Strategy and Equilibrium

Prerequisites

April 2018

1Slide2

Introduction

Presentation builds on Game Theory: Strategy and EquilibriumPurpose is to: extend the concept of strategy extend the characterisation of the equilibrium of a gamePoint of taking these steps: tidy up loose ends from elementary discussion of equilibrium

lay basis for more sophisticated use of gamessome important applications in economicsApril 20182Slide3

Overview

The problem

Mixed strategies

Applications

Games: Equilibrium

An introduction to the issues

April 2018

3Slide4

Games: a brief review

Components of a gameplayers (agents) h = 1,2,…objectives of players rules of play

outcomesStrategysh: a complete plan for all positions the game may reachSh: the set of all possible sh

focus on “best response” of each playerEquilibriumelementary but limited concept – dominant-strategy equilibriummore general – Nash equilibriumNE each player is making the best reply to everyone else

April 2018

4Slide5

NE: An important result

In some cases an important result applieswhere strategy sets are infinite for example where agents choose a value from an interval

THEOREM: If the game is such that, for all agents h, the strategy sets Sh are convex, compact subsets of

and the payoff functions vh are continuous and quasiconcave, then the game has a Nash equilibrium in pure strategies

Result is similar to existence result for General Equilibrium

 

April 2018

5Slide6

A problem?

Where strategy sets are finiteagain we may wish to seek a Nash Equilibriumbased on the idea of best replyBut some games apparently have no NE

example – the discoordination gameDoes this mean that we have to abandon the NE concept?Can the solution concept be extended? how to generaliseto encompass this type of problemFirst, a brief review of the exampleApril 2018

6Slide7

[–]

2,1

0,3

1,2

3,0

[+]

Player

a

Player

b

[+]

[–]

“Discoordination”

If a plays

[–]

then b’s best response is

[+]

If b plays

[+]

then a’s best response is

[

+

]

If a plays

[+]

then b’s best response is

[

]

Apparently, no Nash equilibrium!

Again there’s more to the Nash-equilibrium story here

(to be continued)

If b plays

[

]

then a’s best response is

[

]

Discoordination

This game may seem no more than a frustrating chase round the payoff table. The two players’ interests are always opposed (unlike Chicken or the Battle of the Sexes). But it is an elementary representation of class of important economic models. An example is the tax-audit game where Player 1 is the tax authority (“audit”, “no-audit”) and Player 2 is the potentially cheating taxpayer (“cheat”, “no-cheat”). More on this later.

Story

April 2018

7

* detail on slide can only be seen if you run the slideshowSlide8

Overview

The problem

Mixed strategies

Applications

Games: Equilibrium

Extending

the strategy concept

April 2018

8Slide9

A way forward

Extend the concept of strategynew terminology required Pure strategythe type of strategy that has been discussed so far

a deterministic plan for every possible eventuality in the gameMixed strategya probabilistic approach to playderived from set of pure strategiespure strategies themselves can be seen as special cases of mixed strategiesApril 2018

9Slide10

Mixed strategies

For each player take a set of pure strategies SAssign to each member of S a probability p that it will be playedEnables a “

convexification” of the problemThis means that new candidates for equilibrium can be foundand some nice results can be establishedbut we need to interpret this with careApril 201810Slide11

Strategy space

– extended?Use the example of strategy space in Game Theory: Basics In the simplest case

S is just two blobs “Left” and “Right”

L

Suppose we introduce the probability

p

Could it effectively change the strategy space like this?

R

S

This is misleading

There is no “half-left” or “three-quarters-right” strategy

Try a different graphical representation

April 2018

11Slide12

Strategy – a representation

Draw a diagram in the space of the probabilitiesStart by enumerating each strategy in the set Sif there are n

of these we’ll need an n-dimensional diagramdimension i corresponds to the probability that strategy i is playedThen plot the points (1,0,0,…), (0,1,0,…),

(0,0,1,…),… Each point represents the case where the corresponding pure strategy is playedTreat these points like “radio buttons”: you can only push one down at a timelikewise the points (1,0,0,…), (0,1,0,…),

(0,0,1,…),… are mutually exclusiveLook at this in the case

n

= 2

April 2018

12Slide13

Two pure strategies in

S

p

R

p

L

(1,0)

(0,1)

Cases where

0 <

p

< 1

Probability of playing

R

Playing L with certainty

Probability of playing

L

p

L

+

p

R

= 1

Pure strategy means being at one of the two points (1,0) or (0,1)

Playing R with certainty

But what of the other points?

April 2018

13Slide14

Mixed strategy – a representation

The endpoints (1,0) and (0,1) represent playing the “pure” strategies L and R

Any point on the line joining them represents a probabilistic mixture of L and R:middle of the line represents case where the person spins a fair coin before choosing L or R

pL = pR = ½Consider the extension to the case of 3 pure strategies:

strategies consist of the actions “Left”, “

M

iddle”, “

R

ight”

we now have three “buttons”

(1,0,0)

,

(0,1,0)

,

(0,0,1)

Again consider the diagram:April 2018

14Slide15

Three pure strategies in

S

0

p

R

p

L

p

M

Third axis corresponds to probability of playing “

M

iddle”

(

1,0,0

)

(0,0,1)

(0,1,0)

Three “buttons” for the three pure strategies

Introduce possibility of having

0 <

p

< 1

p

L

+

p

M

+

p

R

= 1

April 2018

15Slide16

Strategy space again

Allowing for the possibility of “mixing”Player’s strategy space consists of a pair:a collection of pure strategies (as before)a collection of probabilitiesOf course this applies to each of the players in the gameHow does this fit into the structure of the game?

Two main issues:modelling of payoffsmodelling and interpretation of probabilitiesApril 201816Slide17

The payoffs

We need to take more care herea question of the nature of “utility”If pure strategies only are relevantpayoffs can usually be modelled simply

usually can be represented in terms of ordinal utilityIf players are acting probabilisticallyconsider how to model prospective payoffstake into account preferences under uncertaintyuse expected utility?Cardinal versus ordinal utility

if we take expectations over many cells of the payoff table……we need a cardinal utility conceptcan transform payoffs u only by scale and origin: a + bu

otherwise expectations operator is meaningless

April 2018

17Slide18

Probability and payoffs

Expected utility approach induces a simple structureWe can express resulting payoff assum of

(utility associated with each button)  (probability each button is pressed)So we have a neat linear relationshippayoff is linear in utility associated with each buttonpayoff is linear in probabilitiestherefore payoff is linear in strategic variables

Implications of this structure?April 201818Slide19

Reaction correspondence

A simple tool build on the idea of the reaction function used in oligopolygiven competitor’s quantity, choose your own quantityBut, because of linearity need a more general concept

reaction correspondencemultivalued at some pointsallows for a “bang-bang” solutionGood analogies with simple price-taking optimisationthink of demand-response with straight-line indifference curvesor straight-line isoquantsComputation of equilibrium need not be difficult

April 201819Slide20

Mixed strategies: computation

To find optimal mixed-strategy:take beliefs about probabilities used by other playerscalculate expected payoff as function of these and one’s own probabilities

find response of expected payoff to one’s own probabilitycompute reaction correspondenceTo compute mixed-strategy equilibriumtake each agent’s reaction correspondence

find equilibrium from intersection of reaction correspondencesPoints to notebeliefs about others’ probabilities are crucialstage 4 above often leads to p = 0 or p = 1

acts like a kind of tipping mechanism

April 2018

20Slide21

Mixed strategies: result

The linearity of the problem permits us to close a gap We have another existence result for Nash EquilibriumTHEOREM Every game with a finite number of pure strategies has an equilibrium in mixed strategies

April 201821Slide22

The random variable

Key to the equilibrium concept: probabilityBut what is the nature of this entity?an explicit generating model?subjective idiosyncratic probability?will others observe and believe the probability?How is one agent’s probability related to another?

do each choose independent probabilities?or is it worth considering a correlated random variable?Examine these issues using two illustrationsApril 201822Slide23

Overview

The problem

Mixed strategies

Applications

Games: Equilibrium

An example where only a mixed strategy can work

The audit game

Chicken

April 2018

23Slide24

Illustration: the audit game

Builds on the idea of a discoordination gameA taxpayer chooses whether or not to report income ypays tax ty if reports

pays 0 if does not report and concealment is not discoveredpays tax plus fine F if does not report and concealment is discoveredTax authority (TA) chooses whether or not to audit taxpayerincurs resource cost c if it auditsreceives due tax

ty plus fine F if concealment is discoveredExamine equilibriumfirst demonstrate no equilibrium in pure strategiesthen the mixed-strategy equilibriumFirst examine best responses of each player to the other

April 2018

24Slide25

[report]

[1

t

]

y

,

ty

[1

t

]

y

,

ty

c

y

, 0

[1

t]

y  F,

ty + F  c

[conceal]

Taxpayer

Tax Authority

[Audit]

[Not audit]

Audit game: normal form

Each chooses one of two actions

(taxpayer, TA) payoffs

If taxpayer conceals then TA will audit

If taxpayer reports then TA won’t audit

[

1

t

]

y

>

[1

t

]

y

F

t

y

+

F

c

> 0

If TA audits then taxpayer will report

t

y

c

>

t

y

y >

[1

t

]

y

If TA doesn’t audit, taxpayer will conceal

No equilibrium in pure strategies

mixed strategies

April 2018

25Slide26

Audit game: mixed strategy approach

Now suppose each player behaves probabilisticallytaxpayer conceals with probability pa TA audits with probability

pb Each player maximises expected payoffchooses own probabilitytaking as given the other’s probabilityFollow through this processfirst calculate expected payoffsthen compute optimal p given the other’s

pthen find equilibrium as a pair of probabilities April 201826Slide27

Audit game: taxpayer’s problem

Payoff to taxpayer, given TA’s value of pb

: if conceals: ua = pb [y 

ty  F] + [1 pb ] y =

y 

p

b

ty

p

b

F

if reports:

u

a = y

 ty If taxpayer selects a value of pa, calculate expected payoffE

ua = pa [y 

pbty  pb

F] + [1 pa ] [y 

ty]= [1  t] y

+ pa [1  pb] ty 

papbF Taxpayer’s problem: choose pa to max Eua Compute effect on

Eua of changing pa :

∂E

u

a

/ ∂

p

a

= [

1

p

b

]

ty

p

b

F

define

p

*b

=

ty

/ [

ty + F] then E u

a / ∂pa is positive if pb < p*b, negative if “>”So optimal strategy is set

pa to its max value 1 if pb is low (below p*b)set pa

to its min value 0 if pb is highApril 201827Slide28

Audit game: TA’s problem

Payoff to TA, given taxpayer’s value of pa:

if audits: ub = pa [ty + F

 c] + [1 pa][ty 

c] =

ty

c

+

p

a

F

if does not audit:

u

b

= pa

∙ 0 + [1 pa]

ty = [1 pa] ty

If TA selects a value of pb, calculate expected payoffE

ub = pb [ty

 c + paF] + [1

 pb] [1 pa] ty

= [1  pa ] ty + papb [

ty + F]  pb

cTA’s problem: choose

p

b

to max

E

u

b

Compute effect on

E

u

b

of changing

p

b

:

E

u

b

/ ∂

p

b

=

pa [ty

+ F]  c define p*a = c / [

ty + F] then E ub / ∂pb is positive if

pa < p*a, negative if “>”So optimal strategy is set pb to its min value 0 if pa

is low (below p*a)set pb to its max value 1 if pa is high

April 201828Slide29

Audit game: equilibrium

1

0

1

p

b

p

a

p

*a

p

*b

The space of mixed strategies

Taxpayer’s reaction correspondence

p

a

= 1 if

p

b

<

p

*b

p

a

= 0 if

p

b

>

p

*b

TA’s reaction correspondence

p

b

= 0 if

p

a

<

p

*a

p

b

= 1 if

p

a

>

p

*a

Equilibrium at intersection

(

p

*

a

,

p

*b

)

April 2018

29Slide30

Overview

The problem

Mixed strategies

Applications

Games: Equilibrium

Mixed strategy or correlated strategy?

The audit game

Chicken

April 2018

30Slide31

Chicken game again

A number of possible background storiesthink of this as individuals’ contribution to a public projectthere’s the danger that one may contribute, while the other “free rides”

and the danger that nobody contributes at allbut this isn’t quite the classic “public good problem” (later)Two players with binary choices call them “contribute” and “not contribute”denote as [+] and [−]Payoff structureif you contribute and the other doesn’t, then you get 1 the other gets 3

if both of you contribute, then you both get 2if neither of you contribute, then you both get 0 First, let’s remind ourselves of pure strategy NE April 2018

31Slide32

[–]

0,0

3,1

1,3

2,2

[+]

Player

a

Player

b

[+]

[–]

Chicken game: normal form

If a plays

[–],

b’s best response is

[+]

If b plays

[+],

a’s best response is

[

]

Resulting NE

By symmetry, another NE

Two NE’s in pure strategies

Up to this point utility can be taken as purely ordinal

mixed strategies

April 2018

32Slide33

Chicken: mixed strategy approach

Each player behaves probabilistically:a plays [+] with probability pa

b plays [+] with probability pb Expected payoff to a is Eu

a = pa [2∙pb +1·[1

−pb]] + [1

p

a

][3

·

p

b

+ 0

·

[1

− pb]] =

pa +3pb − 2pa

pb Differentiating: dE

ua /dpa =1−

2pb which is positive (resp. negative) if pb <

½ (resp. pb > ½)So a’s optimal strategy is

pa =1 if pb < ½ ,

pa = 0 if pb > ½ Similar reasoning for bTherefore mixed-strategy equilibrium is

(pa,pb ) = (

½,½)

where payoffs are

(

u

a

,

u

b

) = (1

½

, 1

½)

April 2018

33Slide34

Chicken: payoffs

u

a

u

b

0

2

3

1

2

3

1

Space of utilities

Two NEs in pure strategies (as before)

Yellow area: possibilities if

utility is thrown away

Green area: utilities achievable by

randomisation

(1

½

, 1

½

):

Mixed-strategy NE

Red broken line: Efficient outcomes

Mid point: equitable and efficient solution?

Utility here must have

cardinal

significance

Equitable and efficient outcome found

by taking

½ each of the two pure-strategy NEs

How can we get this?

(1

½

, 1

½

)

April 2018

34Slide35

Chicken game: summary

If the agents move sequentially then get a pure-strategy NEoutcome will be either (3,1) or (1,3)depends on who moves first If move simultaneously: a coordination problem?

Randomisation by the two agents?independent action does not help muchproduces payoffs (1½, 1½)

But if they use the same randomisation device:play [+] with the same probability p expected payoff for each is u

a = p

+ 3

p

− [

2

p

]

2

= 4

p

[

1 − p ]

maximised where p = ½ Appropriate randomisation seems to solve the coordination problem April 2018

35Slide36

Another application?

Do mixed strategies this help solve Prisoner’s Dilemma? A reexaminationagain model as individuals’ contribution to a public project

two players with binary choices: contribute [+], not-contribute []close to standard public-good problemBut payoff structure crucially different from “chicken”if you contribute and the other doesn’t, you get 0 the other gets 3if both of you contribute, then you both get 2

if neither of you contribute, then you both get 1 We know the outcome in pure strategies:there’s a NE ([], [])but payoffs in NE are strictly dominated by those for ([+

], [+])Now consider mixed strategy

April 2018

36Slide37

PD: mixed-strategy approach

Again each player behaves probabilistically:a plays [+] with probability pa

b plays [+] with probability pb Expected payoff to a is Eua =

pa [2∙pb + 0·[1−p

b]] + [1−p

a

][3

·

p

b

+ 1

·

[1

p

b

]] = 1 + 2p

b − paclearly E

ua is decreasing in paOptimal strategies

from the above, a will set pa to its minimum value, 0

by symmetry, b will also set pb to 0So we are back to the non-cooperative solution :

(pa,pb ) = (

0,0)both play [] with certaintyMixed-strategy approach does not resolve the dilemma

April 201837Slide38

Assessment

Mixed strategy: a key development of game theorycloses a hole in the NE approachbut is it a theoretical artifice?Is mixed-strategy equilibrium an appropriate device? depends on the context of the microeconomic model

degree to which it’s plausible that agents observe and understand the use of randomisationNot the last word on equilibrium conceptsas extra depth added to the nature of gamenew refinements of definitionExample of further developmentsintroduction of time, in dynamic gamesintroduction of asymmetric information

April 201838