Objects Projected Horizontally Horizontal projectile motion horizontally the velocity is always constant 0 vertically the initial velocity y is always zero vertically ID: 483376
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Slide1
Projectile MotionObjects Projected Horizontally
Horizontal projectile motion:
horizontally the velocity () is always constant ( = 0)vertically the initial velocity (y) is always zerovertically the object experiences downward acceleration due to gravity (= 9.81 m/s2)the horizontal and vertical motion is independent of each other except they have a common timethe time it takes for the object to hit the ground is not affected by the horizontal velocity
Slide2
Horizontal (x)
Vertical (y)
(range) (height) (constant) = 0 (constant)
= 0
= 9.81 m/s 2t (same)t (same)
Horizontal (x)Vertical (y)t (same)t (same)
animationSlide3
An object is kicked off a cliff with a horizontal velocity of 4.2 m/s. The height of the cliff is 3.2 m. Calculate the following:
the time the object is airbornethe horizontal displacement when it landsthe velocity upon entering the water[down] = +
ve[right] = +vevertical (y)horizontal (x) = 0 = 9.81 m/s2 = 3.2 mt = ? = ?
= 4.2 m/s = 0
= ?t = ? = 4.2 m/s Slide4
=
t +
3.2 = (0)t +0.5(9.81)4.905 = 3.2t = 0.8077s = 4.2 m/s
t = 0.8077 s
= ?
= t = (4.2)(0.8077) = 3.39 m (a)(b)
=
+ t
= 0 + (9.81)(0.8077)
= 7.924 [down]
(c)
= 4.2 m/s
=
7.924
m/s
=
= 8.9
tan x =
x = 62°
\
The final velocity is 8.9 m/s [62° below the horizontal]
xSlide5
A baseball pitcher throws a ball horizontally. The ball falls 83 cm in travelling 18.4 m to the plate. Determine the ball’s initial horizontal speed.
[down] = +ve[right] = +ve
vertical (y)horizontal (x) = 0 = 9.81 m/s2 = .83 mt = ?
=
? = 0 = 18.4 mt = ?
= t + .83 = (0)t + 0.5(9.81) t = 0.411 s
=
=
= 44.77
\
Initial horizontal speed was 45 m/s [horizontal]Slide6
A tennis player serves a ball horizontally, giving it a speed of 24 m/s [horizontal] from a height of 2.5 m. Calculate the following
:the time the ball is airbornethe horizontal displacementthe velocity at impact[down] = +
ve[right] = +vevertical (y)horizontal (x) = 0 = 9.81 m/s2 = 2.5 mt = ?
= 24 m/s
= 0 = ?
t = ? = t + 2.5 = (0)t + 0.5(9.81)
t = 0.71392 s
=
t
= (24)(0.71392)
= 17.13
\
horizontal displacement was 17 m[horizontal]Slide7
=
+
t = 0 + (9.81)(0.71392) = 7.004 [down] = 24 m/s
= 7.004 m/s
=
= 25
tan x =
x = 16°
\
The final velocity is 25 m/s [16° below the horizontal]
x
= 0
= 9.81
t = 0.71392
= ?