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Critical Path Method Eko Hartanto Critical Path Method Eko Hartanto

Critical Path Method Eko Hartanto - PowerPoint Presentation

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Uploaded On 2018-03-20

Critical Path Method Eko Hartanto - PPT Presentation

Critical Path Method Kegiatan Predecesor Waktu A 8 B 4 C A 10 D A 2 E B 5 F DE 3 Critical Path Method 1 0 0 2 8 8 3 4 10 4 10 15 5 18 18 A8 C10 D2 B4 ID: 658045

method path cost critical path method critical cost 100 total waktu normal aktivitas ongkos kemiringan 150 dan 400 diatas

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Presentation Transcript

Slide1

Critical Path Method

Eko HartantoSlide2

Critical Path Method

Kegiatan

Predecesor

Waktu

A

-

8

B

-

4

C

A

10

D

A

2

E

B

5

F

D,E

3Slide3

Critical Path Method

1

0

0

2

8

8

3

4

10

4

10

15

5

18

18

A/8

C/10

D/2

B/4

E/5

F/3

Total Cost : 100+150+50+100+100+80 = 580Slide4

Critical Path Method

Aktivitas

Normal

Dipercepat

Waktu

Ongkos

Waktu

Ongkos

A

8

100

6

200

B

4

150

2

350

C

10

100

5

400

D

2

50

1

90

E

5

100

1

200

F

3

80

1

100

Data waktu dan ongkos masing-masing kegiatan pada gambar diatas adalah sebagai berikut :Slide5

Critical Path Method

Analisis dari persoalan diatas akan tergantung pada kemiringan garis ongkos dan waktu untuk berbagai aktivitas. Kemiringan garis dapat dihitung :

Cc - Cn

Kemiringan =

Dc – Dn

Dimana

:

- Cc = Cost crash

- Cn = Cost normal

- Dn = Duration normal- Dc = Duration crash

Aktivitas

Kemiringan

A

50

B

100

C

60

D

40

E

25

F

10Slide6

Critical Path Method

1

0

0

2

7

7

3

4

9

4

9

14

5

17

17

A/7

C/10

D/2

B/4

E/5

F/3

Total Cost : 580+50 = 630Slide7

Critical Path Method

1

0

0

2

6

6

3

4

8

4

9

13

5

16

16

A/6

C/10

D/2

B/4

E/5

F/3

Total Cost : 630+50 = 680Slide8

Critical Path Method

1

0

0

2

6

6

3

4

7

4

9

12

5

15

15

A/6

C/9

D/2

B/4

E/5

F/3

Total Cost : 680+60 = 740Slide9

Critical Path Method

1

0

0

2

6

6

3

4

6

4

9

11

5

14

14

A/6

C/8

D/2

B/4

E/5

F/3

Total Cost : 740+60 = 800Slide10

Critical Path Method

1

0

0

2

6

6

3

4

5

4

9

10

5

13

13

A/6

C/7

D/2

B/4

E/5

F/3

Total Cost : 800+60 = 860Slide11

Critical Path Method

1

0

0

2

6

6

3

4

4

4

9

9

5

12

12

A/6

C/6

D/2

B/4

E/5

F/3

Total Cost : 860+60 = 920Slide12

Critical Path Method

1

0

0

2

6

6

3

4

4

4

9

9

5

11

11

A/6

C/5

D/2

B/4

E/5

F/2

Total Cost : 920+(60+10) = 990Slide13

Critical Path Method

Aktivitas

Predesesor

Normal

Percepatan

Time

Cost

Time

Cost

A

-

4

210

3

280

B

-

8

400

6

560

C

A

6

500

4

600

D

A

9

540

7

600

E

D

5

500

2

1100

F

B,C,E

5

150

4

240

G

F

3

150

2

400

H

D

9

600

6

750

Dari tabel aktivitas diatas, hitung :

1). Waktu penyelesaian normal dan ongkosnya !

2). Waktu penyelesaian tercepat dan ongkosnya !