/
Uniform Accelerated Motion Uniform Accelerated Motion

Uniform Accelerated Motion - PowerPoint Presentation

lindy-dunigan
lindy-dunigan . @lindy-dunigan
Follow
508 views
Uploaded On 2016-12-07

Uniform Accelerated Motion - PPT Presentation

Kinematic Equations Measuring Techniques Assess Statements 211 215 217 2110 Due on Wednesday Oct 29 Uniform Accelerated Motion Acceleration The rate at which an objects velocity changes ID: 498610

equation equations acceleration velocity equations equation velocity acceleration variables kinematic step motion rearrange solve average final bus time photogates

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "Uniform Accelerated Motion" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

Uniform Accelerated Motion

Kinematic Equations

Measuring Techniques

Assess

. Statements

2.1.1 –

2.1.5,

2.1.7 –

2.1.10

Due on Wednesday,

Oct. 29Slide2

Uniform Accelerated Motion

Acceleration:

The rate at which an object’s velocity changesUnits = m·s-2Slide3

Measuring Acceleration Experimentally

1 example:

Photogates

: Like you did in this lab, photogates

can be used to determine the time it takes an object to travel a short distance, therefore you can determine instantaneous velocities2 photogates allow you to determine an initial velocity, a final velocity, and a total time between the two.Slide4

Kinematic Equations

Kinematic Equations are considered to be “equations of motion

and are based on the fundamental definitions of average velocity and acceleration:Slide5

Our variables

There are

5

basic variables that are used in any motion-related calculation:Initial Velocity =

v0 or

v

i

or

v

1

or

u

Final Velocity = v or

vf or v

2Acceleration = a

Displacement = d (sometimes also s or could be

Dx)Time = t

Bold face indicates a vector

Each

of the kinematic equations will use

4

of these 5 variablesSlide6

Each of the kinematic equations starts with a rearranged version of the equation for average velocity:

And uses substitution, rearranging, and simplifying the equations to get to the end result.

For

example…

Deriving the

EquationsSlide7

Kinematics Equation

#1

Step 1:

Step 2:

Substitute equation for

Step 3:

Rearrange

acceleration equation to solve for

t

, then

substitute

Step 4: Simplify by multiplying

fractionsStep 5: Rearrange

→Slide8

Kinematics Equation #2

Step 1:

Step 2:

Substitute

Step 3:

Rearrange

acceleration equation to solve for

v

, then

substitute

Step 4: Simplify

Step 5: Distribute the

t through the equation

Step 6: Simplify again

→Slide9

Summary of Equations

You will NOT be required to memorize these

Slide10

Problem Solving Strategy

When given problems to solve, you will be expected to “show

your work”

COMPLETELY!

“Showing work” means that you will be expected to include the following pieces in your full answer (or you will not receive full credit for the problem…)List of variables

– include

units

on this list

Equation

– in variable form

(no

numbers plugged in yet)If necessary, show algebra mid-steps (still no numbers)

Plug in your value(s) for the variables

Final answer – boxed/circled with appropriate units and sig figsSlide11

A school bus is moving at 25 m/s when the driver steps on the brakes and brings the bus to a stop in 3.0 s. What is the average acceleration of the bus while braking?

v =

u

=

t =

a =

Practice Problem #1

25 m/s

0 m/s

3.0 s

?

a

= -8.3

m

/

s

2Slide12

Practice Problem #2

An airplane starts from rest and accelerates at a constant 3.00 m/s

2

for 30.0 s before leaving the ground.(a) How

far did it move?(b) How fast was it going when it took off?v =u

=

t =

a =

s

=

0

m/s

?

30.0 s

3.00 m/s2

s = 1350 m

?

v = 90.0

m

/

s