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Equations of Motion for Uniform Acceleration Equations of Motion for Uniform Acceleration

Equations of Motion for Uniform Acceleration - PowerPoint Presentation

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Equations of Motion for Uniform Acceleration - PPT Presentation

Equations of Motion for Constant Resultant Force Also called because acceleration and resultant force are directly proportional s uvat equations Also called unhelpfully ID: 622796

motion acceleration velocity equations acceleration motion equations velocity write uniform displacement constant find direction units formula called force car fast forget sign

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Slide1

Equations of Motion for Uniform AccelerationSlide2

Equations of Motion for Constant Resultant Force

Also called ….

because………

…acceleration and resultant force are directly proportional. Slide3

s

uvat

equations

Also called ….

(unhelpfully)

Unhelpful because it doesn’t tell us anything about when or how to apply themSlide4

s

uvat

equations

Also called ….

(unhelpfully)

s

– displacement

u – initial velocity

v – final velocity

a – uniform acceleration

t – time between u and v

Slide5

All of these are vectors therefore the sign of each one is very important

The equations have to be homogeneous so make sure your units are

Usually m, s, ms

-1 and ms

-2

s

– displacement

u – initial velocity

v – final velocity

a – uniform acceleration

t – time between u and v

Slide6

Let’s start with straight forward acceleration.

Acceleration = rate of change of velocity

Where’s Carl?

Be careful to get v and u the right way around

This is given on the formula sheet as

 Slide7

Example using

 

A car slows

uniformly from

25 ms

-1

to 10 ms

-1

in 12 s. The car has a mass of 900 kg. What

constant force

do the brakes need to exert?

v

= 10 ms

-1

u

= 25 ms-1t = 12 s

ms

-2

i

.e. an acceleration of ms-2 in the opposite direction to motion 5 NFinal answer 1100 N in the opposite direction to motion

 Slide8

Now displacement…consider the v-t graph

displacement = area under graph

but from

so

(at)

 

0 t

v

uSlide9

Example using

 

How far does the car in the previous example travel while under constant braking?

u

= 25 ms

-1

t

= 12 s

ms

-2

m

What happens if we forget the sign of the acceleration?

 Slide10

Could we have worked this out without

a

?

Yes!

displacement (at constant acceleration) = average velocity x time

This is the same as before from the are under the graph:

Check it

 Slide11

What if we don’t know how long the motion took?

Rearrange the acceleration formula to

and substitute into

Usually given as

 Slide12

We can use this to find out how fast an object will be moving after it has been dropped from rest through a certain distance….

If you fall off a 100m high monument (in vacuum), how fast will you be moving when you hit the floor?Slide13

How do you know which one to use?

Write down what you DO know

a=

s=u=

etcWrite down what you want to find:v=?Look for the formula with JUST a, s, u and vSlide14

Summary - Equations of Motion for Uniform Acceleration

Get yourself a nice drawing

Define the positive direction and stick to it throughout

Write down what you know

Write down what you need to find outLook for the right equationCheck the units are consistent

Be careful with signs

Solve it

Reduce to a sensible number of significant figures

Don’t forget the units