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P. 335 - 342 Sec 3.3 Energy and Efficiency P. 335 - 342 Sec 3.3 Energy and Efficiency

P. 335 - 342 Sec 3.3 Energy and Efficiency - PowerPoint Presentation

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P. 335 - 342 Sec 3.3 Energy and Efficiency - PPT Presentation

2 Law of Conservation Energy cannot be created or destroyed It does not appear or disappear can only be converted from one form to another However we usually find that the output ID: 638078

efficiency energy output 100 energy efficiency 100 output joules input heat device lost mower lose light lawn efficient usable systems mechanical 125

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Presentation Transcript

Slide1

P. 335 - 342

Sec 3.3 Energy and Efficiency

2Slide2

Law of Conservation

Energy

cannot be created or destroyed

.

It does not appear or disappear, can only be

converted from one form to another

.

However, we usually find that the

output

energy

of a device or system is

smaller

than the

input energy

, sometimes much smaller.Slide3

Most often the energy is

lost to heat

.

Example: when heating a pot, not all the heat goes into the pot, some is lost to the surroundings.

Mechanical systems also lose a lot of energy. They lose some energy to

sound, heat from friction

. These are

non-usable forms of energy

.

In fact, all mechanical systems dissipate or lose some energy, so their usable output energy is always less than their input energy.Slide4

Understanding Efficiency

The efficiency of a device is the ration of useful energy that comes out of a device to the total energy that went in

.

The more input energy that a device converts to useable output energy, the more efficient the device is.

Efficiency is usually calculated as a percentage:

% Efficiency =

Joules of useful output

x 100%

Joules of input energySlide5

Example

The efficiency of this light bulb is 5 J/100 J x 100% = 5 %. In other words only

5%

of the energy used is converted to

light

, and the rest is

lost to heat

.

100 J electric energy going in

95 J lost to heat energy

5 J of light energySlide6

Practice:

A diesel truck produces 47.5kJ of useful energy from 125 kJ of diesel fuel. What is the trucks efficiency?

% Efficiency =

Joules of useful output

x 100%

Joules of input energy

% Efficiency =

47.5 kJ

x 100%

125 kJ

% Efficiency = 0.38 x 100%

= 38% efficientSlide7

A lawn mower consumed 8 MJ of chemical energy. The efficiency of this mower is 35% efficient. How much useful output energy did the lawn mower produce?

The lawn mower used 35% of 8 MJ.

0.35 x 8 = 2.8 MJ

% Efficiency =

Joules of useful output

x 100%

Joules of input energy

35% =

Joules of useful output

x 100%

8 MJ

8 MJ x 0.35 = 2.8 MJSlide8

Section 3.4 Reducing the Energy Wasted by Devices

Read pgs 339 - 342Slide9

Assignment:

Page 343

Numbers 2 - 8