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Chapter Five Choice Economic Rationality Chapter Five Choice Economic Rationality

Chapter Five Choice Economic Rationality - PowerPoint Presentation

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Chapter Five Choice Economic Rationality - PPT Presentation

The principal behavioral postulate is that a decisionmaker chooses its most preferred alternative from those available to it The available choices constitute the choice set How is the most preferred bundle in the choice set located ID: 648440

examples choice constrained case choice examples case constrained rational solutions perfect affordable ordinary preferred demands cobb douglas complements kinky

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Slide1

Chapter Five

ChoiceSlide2

Economic Rationality

The principal behavioral postulate is that a decisionmaker chooses its most preferred alternative from those available to it.

The available choices constitute the choice set.

How is the most preferred bundle in the choice set located?Slide3

Rational Constrained Choice

x

1

x

2Slide4

Rational Constrained Choice

x

1

x

2

UtilitySlide5

Rational Constrained Choice

Utility

x

2

x

1Slide6

Rational Constrained Choice

x

1

x

2

UtilitySlide7

Rational Constrained Choice

Utility

x

1

x

2Slide8

Rational Constrained Choice

Utility

x

1

x

2Slide9

Rational Constrained Choice

Utility

x

1

x

2Slide10

Rational Constrained Choice

Utility

x

1

x

2Slide11

Rational Constrained Choice

Utility

x

1

x

2

Affordable, but not the most preferred affordable bundle.Slide12

Rational Constrained Choice

x

1

x

2

Utility

Affordable, but not the most preferred affordable bundle.

The most preferred

of the affordable

bundles.Slide13

Rational Constrained Choice

x

1

x

2

UtilitySlide14

Rational Constrained Choice

Utility

x

1

x

2Slide15

Rational Constrained Choice

Utility

x

1

x

2Slide16

Rational Constrained Choice

Utility

x

1

x

2Slide17

Rational Constrained Choice

x

1

x

2Slide18

Rational Constrained Choice

x

1

x

2

Affordable

bundlesSlide19

Rational Constrained Choice

x

1

x

2

Affordable

bundlesSlide20

Rational Constrained Choice

x

1

x

2

Affordable

bundles

More preferred

bundlesSlide21

Rational Constrained Choice

Affordable

bundles

x

1

x

2

More preferred

bundlesSlide22

Rational Constrained Choice

x

1

x

2

x

1

*

x

2

*Slide23

Rational Constrained Choice

x

1

x

2

x

1

*

x

2

*

(x

1

*,x

2

*) is the most

preferred affordable

bundle.Slide24

Rational Constrained Choice

The most preferred affordable bundle is called the consumer’s

ORDINARY DEMAND

at the given prices and budget.

Ordinary demands will be denoted by

x

1*(p1,p2,m) and x

2

*(p

1

,p

2,m).Slide25

Rational Constrained Choice

When x

1

* > 0 and x

2

* > 0 the demanded bundle is

INTERIOR.If buying (x1*,x2*) costs $m then the budget is exhausted. Slide26

Rational Constrained Choice

x

1

x

2

x

1

*

x

2

*

(x

1

*,x

2

*) is interior.

(x

1

*,x

2

*) exhausts the

budget.Slide27

Rational Constrained Choice

x

1

x

2

x

1

*

x

2

*

(x

1

*,x

2

*) is interior.

(a) (x

1

*,x

2

*) exhausts the

budget; p

1

x

1

* + p

2

x

2

* = m.Slide28

Rational Constrained Choice

x

1

x

2

x

1

*

x

2

*

(x

1

*,x

2

*) is interior .

(b) The slope of the indiff.

curve at (x

1

*,x

2

*) equals

the slope of the budget

constraint.Slide29

Rational Constrained Choice

(x

1

*,x

2

*) satisfies two conditions:

(a) the budget is exhausted; p1x1* + p2

x

2

* = m

(b) the slope of the budget constraint, -p

1/p2, and the slope of the indifference curve containing (x1*,x

2

*) are equal at (x

1

*,x2*).Slide30

Computing Ordinary Demands

How can this information be used to locate (x

1

*,x

2

*) for given p

1, p2 and m?Slide31

Computing Ordinary Demands - a Cobb-Douglas Example.

Suppose that the consumer has Cobb-Douglas preferences.Slide32

Computing Ordinary Demands - a Cobb-Douglas Example.

Suppose that the consumer has Cobb-Douglas preferences.

ThenSlide33

Computing Ordinary Demands - a Cobb-Douglas Example.

So the MRS isSlide34

Computing Ordinary Demands - a Cobb-Douglas Example.

So the MRS is

At (x

1

*,x

2

*), MRS = -p1/p2

soSlide35

Computing Ordinary Demands - a Cobb-Douglas Example.

So the MRS is

At (x

1

*,x

2

*), MRS = -p1/p2

so

(A)Slide36

Computing Ordinary Demands - a Cobb-Douglas Example.

(x

1

*,x

2

*) also exhausts the budget so

(B)Slide37

Computing Ordinary Demands - a Cobb-Douglas Example.

So now we know that

(A)

(B)Slide38

Computing Ordinary Demands - a Cobb-Douglas Example.

So now we know that

(A)

(B)

SubstituteSlide39

Computing Ordinary Demands - a Cobb-Douglas Example.

So now we know that

(A)

(B)

Substitute

and get

This simplifies to ….Slide40

Computing Ordinary Demands - a Cobb-Douglas Example.Slide41

Computing Ordinary Demands - a Cobb-Douglas Example.

Substituting for x

1

* in

then givesSlide42

Computing Ordinary Demands - a Cobb-Douglas Example.

So we have discovered that the most

preferred affordable bundle for a consumer

with Cobb-Douglas preferences

isSlide43

Computing Ordinary Demands - a Cobb-Douglas Example.

x

1

x

2Slide44

Rational Constrained Choice

When x

1

* > 0 and x

2

* > 0

and (x1*,x2*) exhausts the budget,and indifference curves have no

‘kinks’, the ordinary demands are obtained by solving:

(a) p

1

x

1* + p2x2* = y

(b) the slopes of the budget constraint, -p

1

/p

2, and of the indifference curve containing (x

1*,x2*) are equal at (x1*,x2*).Slide45

Rational Constrained Choice

But what if x

1

* = 0?

Or if x

2

* = 0?If either x1* = 0 or x2* = 0 then the ordinary demand (x1*,x

2

*) is at a

corner solution

to the problem of maximizing utility subject to a budget constraint.Slide46

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1Slide47

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1

Slope = -p

1

/p

2

with p

1

> p

2

.Slide48

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1

Slope = -p

1

/p

2

with p

1

> p

2

.Slide49

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1

Slope = -p

1

/p

2

with p

1

> p

2

.Slide50

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1

Slope = -p

1

/p

2

with p

1

< p

2

.Slide51

Examples of Corner Solutions -- the Perfect Substitutes Case

So when U(x

1

,x

2

) = x

1 + x2, the mostpreferred affordable bundle is (x1*,x

2

*)

where

and

if p

1

< p

2

if p

1

> p

2

.Slide52

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

MRS = -1

Slope = -p

1

/p

2

with p

1

= p

2

.Slide53

Examples of Corner Solutions -- the Perfect Substitutes Case

x

1

x

2

All the bundles in the

constraint are equally the

most preferred affordable

when p

1

= p

2

.Slide54

Examples of Corner Solutions -- the Non-Convex Preferences Case

x

1

x

2

BetterSlide55

Examples of Corner Solutions -- the Non-Convex Preferences Case

x

1

x

2Slide56

Examples of Corner Solutions -- the Non-Convex Preferences Case

x

1

x

2

Which is the most preferred

affordable bundle?Slide57

Examples of Corner Solutions -- the Non-Convex Preferences Case

x

1

x

2

The most preferred

affordable bundleSlide58

Examples of Corner Solutions -- the Non-Convex Preferences Case

x

1

x

2

The most preferred

affordable bundle

Notice that the “tangency solution”

is not the most preferred affordable

bundle.Slide59

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1Slide60

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

MRS = 0

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1Slide61

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

MRS = -

¥

MRS = 0

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1Slide62

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

MRS = -

¥

MRS = 0

MRS is undefined

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1Slide63

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1Slide64

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1

Which is the most

preferred affordable bundle?Slide65

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1

The most preferred

affordable bundleSlide66

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1

x

1

*

x

2

*Slide67

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1

x

1

*

x

2

*

(a) p

1

x

1

* + p

2

x

2

* = mSlide68

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1

x

1

*

x

2

*

(a) p

1

x

1

* + p

2

x

2

* = m

(b) x

2

* = ax

1

*Slide69

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

(a) p

1

x

1

* + p

2x2* = m; (b) x2* = ax1*.Slide70

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

(a) p

1

x

1

* + p

2x2* = m; (b) x2* = ax1*.

Substitution from (b) for x

2

* in (a) gives p

1

x

1

* + p

2

ax1* = mSlide71

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

(a) p

1

x

1

* + p

2x2* = m; (b) x2* = ax1*.

Substitution from (b) for x

2

* in (a) gives p

1

x

1

* + p

2

ax1* = mwhich givesSlide72

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

(a) p

1

x

1

* + p

2x2* = m; (b) x2* = ax1*.

Substitution from (b) for x

2

* in (a) gives p

1

x

1

* + p

2

ax1* = mwhich givesSlide73

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

(a) p

1

x

1

* + p

2x2* = m; (b) x2* = ax1*.

Substitution from (b) for x

2

* in (a) gives p

1

x

1

* + p

2

ax1* = mwhich gives

A bundle of 1 commodity 1 unit and

a commodity 2 units costs p1 + ap2;m/(p1 + ap

2

) such bundles are affordable.Slide74

Examples of ‘Kinky’ Solutions -- the Perfect Complements Case

x

1

x

2

U(x

1

,x

2

) = min{ax

1

,x

2

}

x

2

= ax

1