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Allelic Frequencies and Population Genetics Allelic Frequencies and Population Genetics

Allelic Frequencies and Population Genetics - PowerPoint Presentation

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Allelic Frequencies and Population Genetics - PPT Presentation

85 Starter What is the term for all the alleles of all the genes in a population Gene Pool What do you think the term would be for the number of times an allele occurs within a gene pool Allelic Frequency ID: 462576

allele population alleles frequency population allele frequency alleles frequencies weinberg hardy gene number 2pq equation allelic recessive principle work sample moths individuals

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Slide1

Allelic Frequencies and Population Genetics

8.5Slide2

Starter

What is the term for all the alleles of all the genes in a population?

Gene Pool

What do you think the term would be for the number of times an allele occurs within a gene pool?

Allelic FrequencySlide3

Learning Objectives

Describe the terms ‘gene pool’ and ‘allelic frequency’

Explain what the Hardy-Weinberg principle is

Explain how the Hardy-Weinberg principle can be used to calculate allele, genotype and phenotype frequenciesSlide4

Allelic Frequencies

Every person has 2 alleles of a gene (e.g. TT,

Tt

or

tt

)

If a population has 5000 people, then there are 10,000 alleles of each gene

The total number of alleles in a population is said to be 1.0Slide5

Allelic Frequencies

Frequencies of the 2 alleles must add up to 1.0

A recessive/dominant situation

If everyone in a population was TT, then what would the frequency of the T allele be?

If everyone in a population was Tt, then what would the frequency of the T allele be? The t allele?

However, realistically you see a mixture of genotypes in a population, so this way of working out allele frequencies cannot be used. We must use the Hardy-Weinberg Principle

1.0

0.5

0.5Slide6

The Hardy-Weinberg Principle

An equation to work out the frequencies of the alleles in a population

To use the equation the following 5 things must be true:

No mutations

Population is isolated

No selection

Large population

Mating is randomSlide7

The Hardy-Weinberg Principle

The equation = p

2

+ 2pq + q

2

Frequency of allele T = p

Frequency of allele t = q

So, p + q must equal 1.0

Four possible arrangements of the alleles:

TT,

Tt, tT, tt which must equal 1.0

Times them together to create the equation:p2 + 2pq + q2Slide8

Example

Work out, using the Hardy-Weinberg equation, the allele frequencies of cystic fibrosis, a recessive condition affecting the lungs. In a population of 15,000 people, 1 person suffers from the disease.

Recessive, so the frequency of

tt

= 1/15000

So, q

2

= 1/15000 = 0.000067

So,

q =

square root of 0.000067 = 0.0081854 = 0.0082p + q = 1.0

So, 1.0 – q = pp = 1.0 – 0.0082 = 0.9918 (This is the frequency of allele T)Slide9

Example

Now that we know

p

and

q

we can work out the frequency of heterozygous individuals in the population

Heterozygous = 2pq

= 2 x 0.9918 x 0.0082

= 0.0163

This means 163 individuals in 10000 are carriers for the recessive allele and could potentially pass on cystic fibrosis. This is equivalent to 244 people in our 15000.Slide10

Task

Complete application questions on page 127

Not sex linked as approximately equal numbers of males and females in each colour.

562/2215 = 0.254

a) q = Square root of 0.254 = 0.504

b) p + q = 1.0. p = 1.0 – 0.504 = 0.496

c)

Heterozygotes

= 2pq = 2 x 0.496 x 0.504 = 0.5, so

heterozygotes

= 50%

Collect a sample of moths. Mark them unobtrusively. Release back into the population and allow time to mix. Later, randomly catch a sample and count the number of marked and unmarked moths. Calculate by: (total number in first sample x total number of moths in second sample) / number of marked moths recaptured Slide11

Exam Question on H-W

1

.

(a) (q2 = 0.52 / q = 0.72)

(p = 1 – 0.72 = 0.28)

p + q = 1 / p2 + 2pq + q2 = 1 ;

Answer = 2pq / use of appropriate numbers;

Answer = 40%;

3

(b) Any three from: (MARK AS A WHOLE) Small founder population / common ancestor;

Genetic isolation / small gene pool / no immigration / no migration / in-breeding;

High probability of mating with person having H-allele;

Reproduction occurs before symptoms of disease are apparent;

Genetic argument –

Hh

x

hh

® 50% /

Hh

x

Hh

® 75% affected

offspring;

No survival / selective disadvantage;

3 max

Ignore ‘survival of the fittest’

[6]Slide12

Task

You will be given a selection of sweets to represent alleles in a population

The type with fewer present will be the recessive allele and the other the dominant

Work out q, then p

Then calculate the frequency of heterozygous individuals in the population