/
PROJECTILE MOTION Projectile Examples PROJECTILE MOTION Projectile Examples

PROJECTILE MOTION Projectile Examples - PowerPoint Presentation

test
test . @test
Follow
427 views
Uploaded On 2018-03-12

PROJECTILE MOTION Projectile Examples - PPT Presentation

Tennis ball Golf ball Football Softball Soccer ball Bullet Hockey puck Basketball Volleyball Arrow Shot put Javelin These are all examples of things that are projected then go off under the ID: 648461

vertical projectile velocity motion projectile vertical motion velocity problem dart sample gravity horizontal ground angle time banana path initial ball monkey range

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "PROJECTILE MOTION Projectile Examples" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

PROJECTILE MOTIONSlide2

Projectile Examples

Tennis ball

Golf ballFootballSoftballSoccer ballBullet

Hockey puckBasketballVolleyballArrowShot putJavelin

These are all examples of things that are

projected

, then go off under the

influence of gravitySlide3

Not projectiles

Jet plane

RocketCar (unless it looses contact with ground)Slide4

The key to understanding

projectile motion is to realize that gravity acts vertically

it affects only the vertical part of the motion, not thehorizontal part of the motionUnderstanding ProjectilesSlide5

Demonstration

We can see that the horizontal and vertical motions are independent

The red ball falls vertically

The yellow ball was given a kick to the right.They track each other vertically step for step and hit the ground at the same timeSlide6

In the absence of gravity a bullet

would follow a straight line forever.

With gravity it

FALLS AWAY

from

that straight line!

Projectile PathsSlide7

Shoot the MonkeySlide8

Sample Problem

A zookeeper finds an escaped monkey hanging from a light pole. Aiming her tranquilizer gun at the monkey, she kneels 10.0 m from the light

pole,which is 5.00 m high. The tip of her gun is 1.00 m above the ground. At the same moment that the monkey drops a banana, the zookeeper shoots.

If the dart travels at 50.0 m/s,will the dart hit the monkey, the banana, or neither one?Slide9

1 . Select a coordinate system.

The

positive y-axis points up, and the positive x-axis points along the ground toward the pole. Because the dart leaves the gun at a height of 1.00 m, the vertical distance is 4.00 m.

Sample ProblemSlide10

2 . Use the inverse tangent function to find the angle that the initial velocity makes with the

x

-axis.

Sample ProblemSlide11

3 . Choose a kinematic equation to solve for time.

Rearrange the equation for motion along the

x-axis to isolate the unknown Dt, which is the time the dart takes to travel the horizontal distance.

Sample ProblemSlide12

4 . Find out how far each object will fall during this time.

Use the free-fall kinematic equation in both cases.

For the banana,

vi = 0. Thus:

D

y

b

=

½

a

y

(

D

t

)

2

=

½(–9.81 m/s2)(0.215 s)2 = –0.227 m

Sample ProblemSlide13

The dart has an initial vertical component of velocity equal to

v

i sin q

, so:Dyd = (v

i

sin

q

)(

D

t

) +

½

a

y

(

D

t

)2

Dyd

= (50.0 m/s)(sin 21.8)(0.215 s) +

½(–9.81 m/s2)(0.215 s)2

Dyd = 3.99 m – 0.227 m = 3.76 m

Sample ProblemSlide14

5 . Analyze the results.

Find the final height of both the banana and the dart.

ybanana

, f

=

y

b,i

+

D

y

b

= 5.00 m + (–0.227 m)

y

banana

,

f = 4.77 m above the ground

Sample ProblemSlide15

The dart hits the banana.

The slight difference is due to rounding.

y

dart

, f

=

y

d,i

+

D

y

d

= 1.00 m + 3.76 m

y

dart

, f

= 4.76 m above the ground

Sample ProblemSlide16

No gravity is good for kickersSlide17

Newton’s First Law of Motion

“Every object continues in its state of rest, or of uniform motion in a straight line, unless it is compelled to change that state of motion by forces impressed upon it ”

The tendency of matter to maintain its state of motion is known as INERTIA. Slide18

Basketball – without gravitySlide19

Hitting the target – aim high, not directly at the target

BULLSEYE!Slide20

Path of the Projectile

v

Distance downfield

(range)

Height

rising

falling

projectile

g

Horizontal velocity

Vertical

velocity

vSlide21

Horizontal MotionSlide22

Vertical MotionSlide23

Projectile motion – key points

The projectile has both a vertical and horizontal component of velocity

The only force acting on the projectile once it is shot is gravity (neglecting air resistance)At all times the acceleration of the projectile is g = 9.8 m/s2 downward

The horizontal velocity of the projectile does not change throughout the pathSlide24

Key points, continued

On the rising portion of the path gravity causes the vertical component of velocity to get smaller and smaller

At the very top of the path the vertical component of velocity is ZEROOn the falling portion of the path the vertical velocity increasesSlide25
Slide26

More key points

If the projectile lands at the same elevation as its starting point it will have the same vertical SPEED as it began with

The time it takes to get to the top of its path is the same as the time to get from the top back to the ground.The range of the projectile (where it lands) depends on its initial speed and angle of elevationSlide27
Slide28

A

2.00 m tall basketball player wants to make a basket from

a distance of 10.0 m. If he shoots the ball at a 450 angle, atwhat initial speed must he throw the ball so that it goes through the hoop without striking the backboard?

y

x

y

0

Sample ProblemSlide29

Equations

to Choose fromSlide30

Maximum Range

When an artillery shell is fired the initial speed of the projectile depends on the explosive charge – this cannot be changed

The only control you have is over the angle of elevation.You can control the range (where it lands) by changing the angle of elevationTo get maximum range set the angle to 45°Slide31

Interactive

http://galileo.phys.virginia.edu/classes/109N/more_stuff/Applets/ProjectileMotion/jarapplet.html

http://jersey.uoregon.edu/vlab/Cannon/Slide32

Imagine trying to

throw a rock around

the world. If you give it a large horizontal velocity,it will go into orbitaround the earth!

The ultimate

projectile: Orbit