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System of Linear Equations System of Linear Equations

System of Linear Equations - PowerPoint Presentation

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System of Linear Equations - PPT Presentation

with Unique Solution Budi Murtiyasa Universitas Muhammadiyah Surakarta 1 budi murtiyasa linear equation budi murtiyasa linear equation 2 S y stem of linear Equations 2x 1 ID: 813379

budi linear murtiyasa matrix linear budi matrix murtiyasa equation inverse solution system 2x1 2x2 rule cramer

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Slide1

System of Linear Equationswith Unique Solution

Budi MurtiyasaUniversitas Muhammadiyah Surakarta

1

budi murtiyasa / linear equation

Slide2

budi murtiyasa / linear equation

2System

of linear Equations

2x

1

– x

2

+ 2x3 = 7 x1 + 3x2 – 5x3 = 0- x1 + x3 = 4

Using matrix

=

A

X

=

G

3x

1

– 7x

2

+ x

3

= 0

-2x

1

+ 3x2 – 4x3 = 0

Using matrix

=

A

X

=

G

A,

coeficient matrix

X,

variable matrix

G,

constant matrix

Slide3

budi murtiyasa / linear equation

3SYSTEM OF LINEAR

EQUATIONSA X = G

G

=

0

?

YES

HOMOGENEOUS SYSTEM

A X = 0

NO

NONHOMOGENEOUS SYSTEM

A X

=

G, where G

≠ 0example :

3x – 5y + 3z = 0 x + 2y – z = 0

2x + y + 2z = 0

Example:

2x + y – 7z = 03x + 2y + z = 5 x – 6y + 2z = 0

Slide4

budi murtiyasa / linear equation

4Nonhomogeneous S

LE with unique (one) solution

Find the solution of

:

x

1 – 2x2 + x3 = -53x1 + x2 – 2x3 = 11-2x1 + x2 + x

3 = -2

Using a inverse of matrix :

1. Find inverse

of A (by

adjoint matrix).

The solution :

Thus :x

1 = 2x2 = 3x3 = -1

A X = GA

-1 A X = A-1 GX = A-1 G

A

=

,

then

Adj

(A) =

det

(

A) = 6

A-1 =

Adj

(

A)

=

2. X = A

-1

G

X =

=

Slide5

budi murtiyasa / linear equation

5Solve the system using inverse matrix:

x

1

– 2x

2

+ x3 = 0 -2x1 + 3x2 – 4x3

= -8

5x1 + x

2 – x3 =

-4

Slide6

budi murtiyasa / linear equation

6Using inverse matrices, solve the system:x1 – 2x2

+ x3 = -53x1 + x

2

– 2x

3

= 11

-2x1 + x2 + x3 = -2

Slide7

budi murtiyasa / linear equation

7Nonhomogenous SLE with unique

solution

Find a solution of

:

x

1

– 2x2 + x3 = -53x1 + x2 – 2x3 = 11-2x1 + x2 + x

3 = -2

Using Cramer Rule:

finding det

(A), and det

(Ai), that are the determinan

t of

A by replacing the ith

coloumn with constant matrix

G

The solution :

|A| =

= 6

| A1 | =

2. X

i = |A

i | / | A |

= 12

| A

2

| =

= 18

| A

3

| =

= - 6

Slide8

budi murtiyasa / linear equation

8Solve the system : using cramer’s

rule -5x

1

+ 4

x

2

– 2x3 = -10 x1

– 2x2 + x

3 = 2 2x1

+ 3x2 – 4x3 =

-8

Slide9

budi murtiyasa / linear equation

9

Solve the systems below using:

Inverse matrix

Cramer’s rule

Slide10

budi murtiyasa / linear equation

10

Solve the systems below using:

Inverse matrix

Cramer’s rule

Slide11

budi murtiyasa / linear equation

11

Solve the systems below using:

Inverse matrix

Cramer’s rule