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Relations & Their Properties: Relations & Their Properties:

Relations & Their Properties: - PowerPoint Presentation

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Relations & Their Properties: - PPT Presentation

Selected Exercises Copyright Peter Cappello 2011 2 Exercise 10 Which relations in Exercise 4 are irreflexive A relation is irreflexive a A a a R Ex 4 relations on the set of all people ID: 525899

arb antisymmetric exercise step antisymmetric arb step exercise copyright peter cappello 2011 relation bra asymmetric amp prove contradiction relations

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Slide1

Relations & Their Properties: Selected ExercisesSlide2

Copyright © Peter Cappello 2011

2

Exercise 10

Which relations in Exercise 4 are irreflexive?

A relation is

irreflexive

 

a

A (a, a)

R.

Ex. 4 relations on the set of all people:

a

is taller than

b

.

a

and

b

were born on the same day.

a

has the same first name as

b

.

a

and

b

have a common grandparent.Slide3

Copyright © Peter Cappello 2011

3

Exercise 20

Must an asymmetric relation be antisymmetric?

A relation is

asymmetric

 

a

b ( aRb

(b, a)

R ).Slide4

Copyright © Peter Cappello 2011

4

Exercise 20

Must an asymmetric relation be antisymmetric?

A relation is

asymmetric

 

a

b ( aRb

(b, a)

R ).

To Prove:

(

a

b ( aRb

(b, a)

R ) )

(

a

b ( (aRb

bRa )

a = b ) )

Proof:

Assume R is asymmetric.

a

b ( ( a, b )

R

( b, a )

R ).

(step 1. & defn of

)

a

b ( ( aRb

bRa )

a = b )

(

implication

premise is false.)

Therefore, asymmetry implies antisymmetry.Slide5

Copyright © Peter Cappello 2011

5

Exercise 20 continued

Must an antisymmetric relation be asymmetric?

(

a

b ( ( aRb

bRa )

a = b ) )

a

b ( aRb

( b, a )

R )?

Work on this question in pairs.Slide6

Copyright © Peter Cappello 2011

6

Exercise 20 continued

Must an antisymmetric relation be asymmetric ?

(

a

b ( (aRb

bRa )

a = b ) )

a

b ( aRb

(b, a)

R ) ?

Proof that the implication is false:

Let R = { (a, a) }.

R

is

antisymmetric.

R

is not

asymmetric: aRa

(a, a)

R is false.

Antisymmetry thus

does not

imply asymmetry.Slide7

Copyright © Peter Cappello 2011

7

Exercise 30

Let R = { (1, 2), (1, 3), (2, 3), (2, 4), (3, 1) }.

Let S = { (2, 1), (3, 1), (3, 2), (4, 2) }.

What is S

R?

1

2

3

4

R

S

1

2

3

4

S

RSlide8

Copyright © Peter Cappello 2011

8

Exercise 50

Let R be a relation on set A.

Show:

R is antisymmetric

R

R

-1

{ ( a, a ) | a

A }.

To prove:

R is antisymmetric

R

R

-1

{ ( a, a ) | a

A }We prove this by contradiction.R  R-1  { ( a, a ) | a  A }

 R is antisymmetric.We prove this by contradiction.Slide9

Copyright © Peter Cappello 2011

9

Exercise 50

Prove R is

antisymmetric

R

R

-1

{ ( a, a ) | a

A }.

Proceeding by contradiction,

assume

that:

R is

antisymmetric

:

a

b ( (

aRb

 bRa )  a = b ).It is not the case that

R  R-1  { ( a, a ) | a  A }. a b (a, b) 

R  R-1, where a  b. (Step 1.2)aRb , where a 

b. (Step 2)

aR-1

b, where a  b. (Step

2)bRa

, where a  b. (Step 5 &

defn of R-1)

R is not

antisymmetric, contradicting

step 1. (Steps 3 & 5)

Thus, R is

antisymmetric  R 

R-1  { ( a, a ) | a 

A }. Slide10

Copyright © Peter Cappello 2011

10

Exercise 50 continued

Prove R

R

-1

{ ( a, a ) | a

A }

R is

antisymmetric

.

Proceeding by contradiction,

assume

that:

R

R

-1

{ ( a, a ) | a  A }.R is not antisymmetric:

¬a b ( ( aRb  bRa )  a = b ) a b (

aRb  bRa  a  b ) (Step 1.2)bR-1a, where a  b.

(Step 2s & defn. of R-1)( b, a )  R  R-1 where a  b, contradicting step 1. (Step 2 & 3)Thus, R  R-1

 { ( a, a ) | a  A }

 R is antisymmetric.