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G.K.BHARAD INSTITUTE OF ENGINNERING G.K.BHARAD INSTITUTE OF ENGINNERING

G.K.BHARAD INSTITUTE OF ENGINNERING - PowerPoint Presentation

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G.K.BHARAD INSTITUTE OF ENGINNERING - PPT Presentation

DivD sub Calculus Subcode21100 Prepaid byPurohit Vivek D Amipara Hardik J Desai Hiten R ID: 931861

rule fun sin log fun rule log sin cons diff cos line cosec multiplication cot slope tangent functionthe sec

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Slide1

G.K.BHARAD INSTITUTE OF ENGINNERING

Div.:-D

sub.:- Calculus Sub.code:21100

Prepaid by:-Purohit Vivek D.

Amipara Hardik J.

Desai Hiten R.

Godhani Kajal S.

Slide2

Basic DerivationContentWhat is derivation?Derivation of trigonometry functionDerivation’s rules

Slide3

What is a derivative?A functionthe rate of change of a functionthe slope of the line tangent to the curve

Slide4

The tangent line

single point

of intersection

Slide5

slope of a secant line

a

x

f(x)

f(a)

f(a) - f(x)

a

-x

Slide6

Diff. of trigonometric functiond/dx [cos(x)] = sin(x)d/dx [sin(x)] = cos(x)d/dx [tan(x)] = sec2(x)d/dx [cot(x)] = -cosec2(x)d/dx [sex(x)] = sec(x) tan(x)d/dx [cosec(x)] = -cosec(x) cot(x)d/dx [(e)x] = (e)x

Slide7

Rule No. 1(Fun.)Cons. =(Cons.) (Fun.)Cons.-1 (Diff.of Fun.)E.X.:- 1. d/dx [(x)3] = (3)(x)3-1 (1) 2. d/dx [sin3 x] = (3)[sin2 x] [cos x]

Slide8

Rule No. :- 2(Cons.)Fun. = (Cons.)Fun.[log(Cons.)](Diff.of Fun.)E.X. :- 1. d/dx [(2)x ]= (2)x [log(2)] (1) 2. d/dx [(5)sin x ]= (5)sin(x) [log(5)] [cos x]

Slide9

Rule No. :- 3 (multiplication rule)(Fun.)1(Fun.)2 = d/dx (Fun.)1(Fun.)2+d/dx(Fun.)2(Fun.)1E.X. :- 1.d/dx {[(e)x][x2]} = [(e)x][x2]+[(e)

x

][2X]

Slide10

Rule No. :- 4 (division rule)(Fun.)1/(Fun.)2 = {(Fun.)2d/dx (Fun.)1 – (Fun.)1d/dx(Fun.)2}/[(Fun)2]2E.X. :- 1.d/dx(sin x/x) = [x cos x – sin x]/x2

Slide11

Rule No. :- 5y = (Fun.)1(Fun.)2 Take both side log log y = (Fun.)2 log(Fun.)1 Diff. w.r.t. x dy/dx = y[multiplication rule of diff.]E.X.:- 1. y = xx dy/dx = y[x/x + log x] = xx

(1 + log x)

Slide12

Diff. of inverse trigonometric formulasin-1 x = 1/(1 – x2)1/2cos-1 x = -1/(1 – x2)1/2tan-1 x = 1/(1 + x2 )cot-1 x = -1/(1 + x2

)

sec

-1

x = 1/|x|(x

2

– 1)

1/2

cosec

-1

x = -1/|x|(x2 – 1)

1/2

Slide13

E.X.:- 1.(sin-1 x) (x) {Using multiplication rule} = (sin-1 x)(1) + (x) [1/(1 – x2)1/2

Slide14

THANK YOU

THANK YOU