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Electricity and Magnetism Electricity and Magnetism

Electricity and Magnetism - PowerPoint Presentation

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Electricity and Magnetism - PPT Presentation

Physics 208 Dr Tatiana Erukhimova Lecture 3 A charged particle with positive charge q 1 is fixed at the point x a y b y x q 1 q 2 a c d b What are the ID: 405287

force charge total test charge force test total charges chunk rod line positive smeared point length density volume distance fixed suppose particle

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Slide1

Electricity and Magnetism

Physics 208

Dr. Tatiana Erukhimova

Lecture 3Slide2

A charged particle with positive charge

q

1

is fixed at the point x=a,

y

=b.

y

x

q

1

q

2

a

c

d

b

What are the

x

and

y

components of the force on a particle with positive charge

q

2

which is fixed at the point

x = c, y = d?

QuizSlide3
Slide4
Slide5

The negative charge of electron has exactly the same magnitude as the positive charge of the proton.

Neutral atom

Positive ion

Negative ionSlide6

Charging of neutral objects

By contact:

a)

b)Slide7

How you can make a balloon stick to the wall?

Slide8

Principle of Superposition

(revisited)

The presence of other charges does not change the force exerted by point charges. One can obtain the total force by adding or superimposing the forces exerted by each particle separately.

Suppose we have a number

N

of charges scattered in some region. We want to calculate the force that all of these charges exert on some test charge .Slide9

We introduce the charge density or charge per unit volume

How do we calculate the total force acting on the test charge ? Slide10

We chop the blob up into little chunks of volume ; each chunk contains charge . Suppose there are

N

chunks, and we label each of them with some index .

Let be the unit vector pointing from th chunk to the test charge; let be the distance between chunk and test charge. The total force acting on the test charge is

This is approximation!Slide11

The approximation becomes

exact

if we let the number of chunks go to infinity and the volume of each chunk go to zero – the sum then becomes an integral:

If the charge is smeared over a

surface

, then we integrate a

surface

charge density over the area of the surface

A

:

If the charge is smeared over a

line

, then we integrate a

line

charge density over the area of the length:Slide12

Problem 6 page 10

Suppose a charge were fixed at the origin and an amount of charge Q were uniformly distributed along the x-axis from x=a to x=a+L

. What would be the force on the charge at the origin? Slide13

Another example on force due to a uniform line charge

A rod of length L has a total charge Q smeared uniformly over it. A test charge q

is a distance a away from the rod’

s midpoint. What is the force that the rod exerts on the test charge?Slide14

Another example on force due to a uniform line charge

A rod of length L has a total charge Q smeared uniformly over it. A test charge q

is a distance a away from the rod’

s midpoint. What is the force that the rod exerts on the test charge?Slide15

Have a great day!

Hw: All Chapter 2 problems and exercises

Reading: Chapter 2