Let 1 2 3 0 1 where is a constant such that 1 0 Then we see that 1 1 1 1 1 1 0 But 1 0 Hence 0 for all values of That is to say 1 2 3 4 1 1 2 2 3 1 But it is known that 2 Putting 1 in 1 and using 2 we obtain 1 1 2 2 3 3 4 3 1 2 3 4 3 2 ID: 23126
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