/
Solve Linear Systems by Substitution Solve Linear Systems by Substitution

Solve Linear Systems by Substitution - PowerPoint Presentation

liane-varnes
liane-varnes . @liane-varnes
Follow
348 views
Uploaded On 2018-09-22

Solve Linear Systems by Substitution - PPT Presentation

What does solving a system mean In yesterdays homework we investigated Cool Copy Company and Bountiful Brochures What happened when you graphed the lines The lines intersected What does that intersection mean ID: 675081

system equation step solve equation system solve step linear solution substitute equations true lines pair method check intersect variable

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "Solve Linear Systems by Substitution" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

Solve Linear Systems by SubstitutionSlide2

What does solving a system mean?

In yesterday’s homework, we investigated Cool Copy Company and Bountiful Brochures.

What happened when you graphed the lines?The lines intersected.What does that intersection mean?The two companies sold the same number of copies for the same amount of money.The point of intersection is called “Solving the System.”A “System” is a pair of linear equations.Slide3

3 ways to solve a system:

Graphing

This method is only successful if you draw an accurate graph.SubstitutionThis method has you substitute one equation into another equation and solve.We will learn this method today.

EliminationThis method is used when the equation is in standard form.We will learn this method later in the unit.Slide4

Steps to solve a linear system by substitution

Step 1:

Solve one of the equations for one of its variables.Step 2: Substitute this expression into the other equation and solve for the other variable.Step 3: Substitute this value into the revised first equation and solve.Step 4: Check the solution pair in each of the original equations.

Remember, solving a system of linear equations means that you are finding where the two lines intersect.Slide5

Practice #1:

Find the solution to the linear system:

y = x – 34x + y = 32Step 1: One of the equations is already solved for one variable, y = x – 3Step 2: Substitute “x – 3” in for “y” in the 2nd equation.4x + (x – 3) = 324x + x – 3 = 325x – 3 = 32 +3 +3

5x = 35 5 5x = 7Step 3:

Substitute “7” in for “x” in the first equation, then solve.

y = x – 3

y = 7 – 3

y = 4

The solution to this linear system is an ordered pair,

(7, 4).

This is where the two lines intersect.

Step 4:

Check the solution in each equation.

y = x – 3

4 = 7 – 3

4 = 4 (true)

4x + y = 32

4(7) + 4 = 32

28 + 4 = 32

32 = 32 (true)Slide6

Practice #2:

Find the solution to the linear system:

y = x + 43x + y = 16Step 1: One of the equations is already solved for one variable, y = x + 4Step 2: Substitute “x + 4” in for “y” in the 2nd equation.3x + (x + 4) = 163x + x + 4= 164x + 4 = 16

- 4 - 44x = 12 4 4x = 3

Step 3:

Substitute “3” in for “x” in the first equation, then solve.

y = x + 4

y = 3 + 4

y = 7

The solution to this linear system is an ordered pair,

(3, 7).

This is where the two lines intersect.

Step 4:

Check the solution in each equation.

y = x + 4

7 = 3 + 4

7 = 7 (true)

3x + y = 16

3(3) + 7 = 16

9 + 7 = 16

16 = 16 (true)Slide7

Practice #3:

Find the solution to the linear system:

x – y = 22x + y = 1Step 1: Solve the 1st equation for one variable.x – y = 2 + y +yx = 2 + y

Step 2: Substitute “2 + y” in for “x” in the 2nd equation.2x + y = 12(2 + y) + y = 14 + 2y + y = 14 + 3y = 1

-4 -4

3y

=

-3

3 3

y = -1

Use distributive property.Slide8

Step 3:

Substitute “-1” in for “y” in the first equation, then solve.x – y = 2

x – –1 = 2x + 1 = 2 -1 -1x = 1The solution to this linear system is an ordered pair, (1, -1). This is where the two lines intersect.Step 4: Check the solution in each equation.x – y = 2

1 – –1 = 21 + 1 = 22 = 2 (true)2x + y = 1

2(1)

+

-1

= 1

2

+

-1

=

1

1

= 1

(true)