I bÐ line 3 shows no gal activity and by eliminationmust represent the lacZ geneMutations in the operator will be cisdominant and will cause constitutiveexpression of the lacZ gene only if i ID: 855312
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1 of the lac repressor. Therefore, the lac
of the lac repressor. Therefore, the lac operon associated with the Ocoperator cannot be turned off. Because an operator controls only the genes on thesame DNA strand, it is cis (on the same strand) and dominant (cannot be turnedoff). I). bÐ (line 3) shows no §-gal activity and by eliminationmust represent the lacZ gene.Mutations in the operator will be cis-dominant and will cause constitutiveexpression of the lacZ gene only if itÕs on the same chromosome. Line 6 hascÐ on the same chromosome as b+ but the phenotype is still inducible(owing to c+ in trans). Line 7 has aÐ on the same chromosome as b+ and isconstitutive even though the other ch
2 romosome is a+. Therefore a Thereare als
romosome is a+. Therefore a Thereare also mutations of the repressor that fail to bind inducer (allolactose) and lacIÐ (fails to bind DNA and is recessive). It is possible that line 3, line 4,and line 7 have lacIs mutations (because dominance cannot be ascertained ina cell that is also lacOc) but the other c it is cis to a lacZ+ gene, but the permease is operon.d. Same as part c.e. There is no functional repressor made (and one operator is mutant as well).f. Same as part b.g. Both operators are wild type and the one functional copy of lacI will directthe synthesis of enough repressor to control both operons.9.The term epigenetic inheritance is