with random diagonal unitaries Yoshifumi Nakata Universitat Autonoma de Barcelona amp The University of Tokyo arXiv150207514 amp arXiv150905155 Joint work with C Hirche C Morgan and A Winter ID: 573940
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Slide1
Decoupling with random diagonal-unitaries
Yoshifumi NakataUniversitat Autonoma de Barcelona & The University of Tokyo arXiv:1502.07514 & arXiv:1509.05155Joint work with C. Hirche, C. Morgan, and A. Winter
2 September 2016
Asian Quantum Information Processing Slide2
OutlineIntroductionDecouplingHaar random
unitaries and unitary t-designsDecoupling with random diagonal-unitaries (RDU)Basic ideaDecoupling with RDUsEfficient implementations of RDUsBy quantum circuitsBy Hamiltonian dynamicsConclusion and open questionsSlide3
What is Decoupling?
Choose a good unitary such that where
and
.
Choi-
Jamiolkowski
state of the CPTP map.
Reference
Alice
Bob
qubits
CPTP mapSlide4
What is Decoupling?
Decoupling is
NOT always possible:E.g.
is entangled, the CPTP map is an identity map
.
Reference
Alice
Bob
qubits
CPTP map
When
and
How
can we achieve decoupling?Slide5
Why do we care?
Decoupling
provides a free decoder in Q. capacity theorems.plays key roles in
fundamental physics:Black hole information science & Thermalisation phenomenaMicroscopic dynamics of decoupling is NOT
fully understood.
Reference
Alice
Bob
qubits
CPTP map
When
and
How
can we achieve decoupling?
One of the questions in this talk.Slide6
What is Decoupling?
How?
Choose
to be a Haar random unitary.
When?
Reference
Alice
Bob
qubits
CPTP map
When
and
How
can we achieve decoupling?
A unitary drawn
uniformly at random
w.r.t. the
Haar
measure.Slide7
What is Decoupling?
How?
Choose
to be a Haar random
unitary.When?When the decoupling rate is small.
Reference
Alice
Bob
qubits
CPTP map
When
and
How
can we achieve decoupling?
[
Duplis
et.al ’09
]
A
-approximate
unitary
2-design!
A
-approximate unitary 2-design
A random unitary that simulates the
2
nd
order statistical moments
(e.g. Variance) of a
Haar
random unitary
within an error
.
Slide8
Decoupling Theorem
If
,
decoupling
is achieved at the rate of
.
Natural questions:
Is this result
tight
?
Do we really need
to achieve decoupling
?
(Larger
is easier to implement.)
Decoupling with approximate designs
[
Szehr
et.al ’11]
For a
-
approximate
unitary 2-design
where and
.
Slide9
Questions in this talkQuestionsCan we achieve decoupling by
-approximate 2-designs where ?Physically natural realisation of decoupling? In this talkWe provide a
new construction of decoupling, based on random diagonal-unitaries
.We show that
is
NOT
necessary.
decoupling can be
realised
by
periodically changing spin-glass-type Hamiltonians
.
Slide10
OutlineIntroductionDecouplingHaar random unitaries and unitary t-designs
Decoupling with random diagonal-unitaries (RDU)Basic ideaDecoupling with RDUsEfficient implementations of RDUsBy quantum circuitsBy Hamiltonian dynamicsConclusion and open questionsSlide11
Basic idea
To use random
unitaries diagonal in the Z- and X-basis
All of and
are randomly and independently chosen from
.
Repeat
and
many times:
Each
and
are independent and random
.
CPTP mapSlide12
Basic idea
Why
do we expect
it works
?
The
is
a unitary
t
-design,
if
(in preparation
).
Every time,
and
are chosen independently at random.
U(d)Slide13
Decoupling with
qubits
CPTP map
Decoupling Theorem
[YN, CH, CM, and
AW:
arXiv
:
1509.05155
]
For
, the following holds:
is
sufficient to achieve decoupling.
Slide14
Decoupling with
qubits
Decoupling Theorem’
[YN, CH, CM, and AW:
arXiv
:
1509.05155
]
When the CPTP map is the
partial trace
, for
,
is
sufficient to achieve decoupling.
In
the
most important cases of the
partial
traces,
suffices.
Slide15
Proof SketchAn upper bound of ?It’s obtained from the operator In terms of ,
Use the key lemma for (arXiv: 1502.07514).Still complicated, but durable
qubits
CPTP map
Alice
Ãlice
Reference
M.E.S
ReferenceSlide16
How good approximate 2-designs are they?the
is
.the
is
.
Decoupling and 2-designs
Decoupling Theorem
[YN, CH, CM, and AW:
arXiv
:
1509.05155
]
The
for
(
) achieves decoupling at the rate of
for any CPTP (partial traces) map.
An
-app. 2-design is
NOT
necessary for decoupling.
Theorem
[YN, CH, CM, and AW,
arXiv
:
1502.07514
]
The
on
qubits is a
-
approximate unitary 2-design, where
.
Slide17
Are these results optimal?Converse statement (weak)
Conjecture: () suffices for any CPTP (partial traces) map.
CPTP map
CPTP map
Decoupling!
Decoupling!Slide18
Outline
Introduction
DecouplingHaar
random unitaries and unitary t-designsDecoupling with random diagonal-unitaries
(RDU)Basic ideaDecoupling with RDUs
Efficient implementations of RDUs
By quantum circuits
By Hamiltonian dynamics
Conclusion and open questionsSlide19
Implementation of
Both and use exponentially many random numbers. in N-qubit systems. No way to implement efficiently...A way of approximating lower order properties of is known
[YN, Koashi, Murao ’14]
.
Slide20
Quantum circuits
Up to the
2
nd
order
(
(
.
All gates in the
part are
commuting
.
can be applied
simultaneously
=
Short
implementation.
Up to the 2
nd
orderSlide21
Hamiltonian dynamicsDecoupling by spin-glass type Hamiltonians.The time necessary to achieve decoupling is independent of the number of particles.All-to-all interactions are maybe feasible in cavity QED or in semiquantal spin gasses.
4
5
6
Time
Hamiltonian
7
Decoupled!!Slide22
ConclusionWe have presented a new construction of decoupling based on random X- and Z-diagonal unitaries.
We have shown that () suffices to achieve decoupling for any CPTP (partial traces) map, implying
precise designs are not needed.
Decoupling can be achieved by simple quantum circuits.Decoupling can be realised by
periodically changing spin-glass-type Hamiltonians.
CPTP mapSlide23
Open questionsAre 2-designs really needed to achieve decoupling at the rate of
?Many believe NO. Nobody knows how to show that.1-designs cannot, what is 1.5-designs?In decoupling with , how many repetitions are needed?Conjecture: suffices for any CPTP map.Is it possible to achieve decoupling by time-independent Hamiltonians?In closed systems, Hamiltonians should be time-indep…Thank you for your attention!