Day 64 – Density Mixture problems - PowerPoint Presentation

342 views
Uploaded On 2020-11-06

Day 64 – Density Mixture problems - PPT Presentation

PERCENT x PERCENT x PERCENT x AMOUNT AMOUNT AMOUNT THE EQUATION IS PERCENT x AMOUNT PERCENT x AMOUNT PERCENT x AMOUNT EXAMPLE How many gallons on a 12 salt solution must be combined with a 42 salt solution to obtain 30 gallons of an 18 solution ID: 816376

boat time downstream drive time boat drive downstream formula speed computer upstream column problems rate solution miles noya

Link:

Copy

Embed:

<iframe width="560" height="315" src="https://www.docslides.com/embed/816376" frameborder="0" allowfullscreen></iframe>

Download Presentation from below link

Download The PPT/PDF document "Day 64 – Density Mixture problems" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.

Presentation Transcript

Slide1

Day 64 – Density

Slide2

Mixture problems

PERCENT

+PERCENTx=PERCENTxAMOUNTAMOUNTAMOUNT

THE EQUATION IS:

(PERCENT x AMOUNT) + (PERCENT x AMOUNT) = (PERCENT x AMOUNT)

Slide3

EXAMPLE

How many gallons on a 12% salt solution must be combined with a 42% salt solution to obtain 30 gallons of an 18% solution?

12%

42%18%x+30 – x =30

24 gallons

of the 12% salt solution must be used.

Slide4

INVESTMENT Problems Are A Type Of Mixture Problems

EXAMPLE:

If you have twice as much invested at 8% as at 5% and if your annual interest income from these two investments is $315, how much is invested at each rate?

5%8%x+2x=315

$1500

at 5% and

$3000

at 8%

Slide5

MOTION

problems

RTABTHREE COLUMNS: 1. GIVEN You are given the two distances, and the two rates, or the two times. 2. UKNOWN Read the question to determine this column. 3. FORMULA D = RT R = D/T T= D/R THE EQUATION COMES FROM THE FORMULA COLUMN!!!

Slide6

EXAMPLE

The speed of a stream is 4 m/h. A boat travels 36 miles downstream in the same time it travels 12 miles upstream. Find the speed of the boat in still water.

THREE COLUMNS:

1. GIVEN You are given the two DISTANCES, 36 miles downstream and 12 miles upstream. 2. UKNOWN You are asked to find the speed (RATE) of the boat in still water. Let this be x. Keep in mind that all entries in the table apply to the boat in this stream, which is moving at a speed of 4 m/h. Therefore, the rate of the boat going downstream is x + 4 m/h, and the rate of the boat going upstream is x – 4 m/h. 3. FORMULA The remaining column is the TIME column, and the formula for time is T = D/R; hence, the time going downstream is 36/(x+4) and the time going upstream is 12/(x-4).

Slide7

DOWNSTREAM36x + 436/(x + 4)UPSTREAM12x – 412/(x – 4)Since the EQUATION come from the FORMULA COLUMN, we must read the problem again and find a relation between the two TIMES. It says the boat travels downstream and upstream “in the SAME TIME,” hence

The speed of boat in still water is

8 m/h

Slide8

Word Problem Examples

Noya

drives into the city to buy a software program at a computer store. Because of traffic conditions, she averages only 15 mi/h. On her drive home she averages 35 mi/h. If the total travel time is 2 hours, how long does it take her to drive to the computer store?

Slide9

Answer

Define

Let time of

Noya’s drive to the computer store.Let t = the time of Noya’s drive home. 2 ─ t = the time of Noya’s drive home.Relate Part of Noya’ TravelRateTime DistanceDistanceTo the computer store15t15tReturn Home

2 ─ t

35(2 ─ t)

Slide10

Write

It took

Noya

1.4h to drive to the computer.