Structure conditioning strategy and toy model A.

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Description: Structure conditioning strategy and toy model A. Degiovanni, J. Giner Navarro, W. Wuensch 02.04.2014 CLIC RF Structure Development Meeting Outline PART 1: conditioning strategy picture of the current conditioning strategy proposal of

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slide1. Structure conditioning strategy and toy model A. Degiovanni, J. Giner Navarro, W. Wuensch
02.04.2014
CLIC RF Structure Development Meeting<br>
slide2. Outline PART 1: conditioning strategy
picture of the current conditioning strategy
proposal of alternative conditioning strategy based on the previous presentation

PART 2: conditioning process
empirical observations
“pivot” toy model A.D 02.04.2014 2<br>
slide3. Picture of the current conditioning strategy 3 1. Conditioning at constant BDR obtained in Xbox1 with long term conditioning algorithm 2. Over shoot and back off to nominal gradient 3. Long term run at 100 MV/m, with typical reduction in BDR A.D 02.04.2014<br>
slide4. Comparison of E0* vs #BD 4 A.D 02.04.2014 Same conditioning level at different number of BD.<br>
slide5. Alternative approach to conditioning: A.D 02.04.2014 5 During conditioning never exceed specs. option 1 option 2<br>
slide6. PART 2: conditioning process Empirical observations about “conditioning”:
during conditioning we can reach higher gradients at a fixed BDR,
at a fixed gradient, the BDR drops with time.

Some questions:
can we go to infinitely high gradients?  probably not
can we think to reduce the BDR to extremely low values?
is the dependence between BDR and E0 fixed in time?

What is presented here is a “toy-model”, a graphical way of thinking about how conditioning works, to trigger the discussion A.D 02.04.2014 6<br>
slide7. 7 BDR summary on TD24
comparing to T24 T. Higo, LCWS2012 at Arlington Comparing to T24#3, TD24#4 behaves poor. A.D 02.04.2014<br>
slide8. T. Higo, ‘CLIC Workshop 2014’ A.D 02.04.2014 8<br>
slide9. Pivot toy-model 2 assumptions:
there is a threshold for the maximum field at which a structure can run and this threshold is fixed by the condition BDR = 1 [bpp]
the BDR vs E0 lines are pivoting around this point (=the exponent describing the BDR vs E0 dependence is not constant in time, but increases as a function of conditioning or number of pulses)

Under these assumptions:
at a fixed BDR we can reach higher gradients until the ultimate limit is hit
at a fixed gradient, the BDR drops with time

2 simplifications:
just assume constant pulse length
assume limit on E field (could be Sc ! ) A.D 02.04.2014 9<br>
slide10. Picture of conditioning with pivot model 10 conditioning testing at fixed gradient A.D 02.04.2014<br>
slide11. Pivot model BDR = 1 (limit for operation by definition) Emax (assumed limit for gradient) The exponent X increases with the number of pulses (n) log(BDR)=X(n)*log(E0) Emeas = α Emax 11 70 80 90 100 110 120 130 140 155 A.D 02.04.2014<br>
slide12. Conclusion/discussion and experiment proposal Conditioning strategy
alternative conditioning strategy (= never exceeding specs.), if conditioning is a function of number of pulses and not of number of BDs

Conditioning process
“pivot” toy model has been presented as a graphical tool to visualize the conditioning process
measurements of BDR vs E0 as a function of number of pulses are needed to validate it
 DC spark at high rep rate (1kHz) good candidate A.D 02.04.2014 12<br>
slide13. пи́во model 13 A.D 02.04.2014<br>
slide14. thank you for your attention A.D 02.04.2014 14<br>
slide15. extra slides A.D 02.04.2014 15<br>
slide16. log(BDR)=X(n)*log(E0) X(n) = X0 + q n From experiments we know: Let’s define:
b := log(BDR)
e := log(E0)
E0,meas / E0,max = α Let’s assume a linear increase of X with the number of pulses n: b(n) = (X0 + q n) log(α) Combining the two equations we have: b(n) = [X0 log(α)] + [q log(α)] n X0 log(α) = -4.7 [bpp]
q log(α) = -4.7 10-4 [1/hrs] From T. Higo, ‘CLIC Workshop 2014’ log(BDR) = -4.7 10-4x - 4 16 at 50 Hz A.D 02.04.2014<br>
slide17. X0 log(α) = -4.7
q log(α) = -4.7 10-4 [1/hrs] Depending of the value of α, it exists a family of curves X(n) that satisfies the two conditions: Every α corresponds to a different value of Emax, assuming the measurements were performed at Emeas = 100 MV/m For α = 0.65 , X(n) ∈ [25; 38] for n < 5000 hrs and X0 = 25
q = 2.5 10-3 [1/hrs] or
1.7 /month(50Hz) 17 A.D 02.04.2014<br>
slide18. Picture of conditioning 18 conditioning testing at fixed gradient A.D 02.04.2014<br>
slide19. full run A.D 02.04.2014 19<br>
slide20. long term behaviour 20 A.D 02.04.2014<br>