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Limiting Reagents and Percent Yield Limiting Reagents and Percent Yield

Limiting Reagents and Percent Yield - PowerPoint Presentation

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Limiting Reagents and Percent Yield - PPT Presentation

Yesits still stoichiometry Think about making grilled cheese To make a decent grilled cheese sandwich you need two pieces of bread 2 pieces of cheese and 1 pat of butter Write an equation that describes making a grilled cheese sandwich ID: 556159

cheese yield limiting reagent yield cheese reagent limiting percent problem bread butter excess actual theoretical grilled stoichiometry sandwiches problems reaction pieces solve

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Slide1

Limiting Reagents and Percent Yield

Yes…it’s still stoichiometry…Slide2

Think about making grilled cheese…

To make a

decent

grilled cheese sandwich, you need two pieces of bread, 2 pieces of cheese, and 1 pat of butter. Write an equation that describes making a grilled cheese sandwich.

2 Bread + 2 Cheese + 1 Butter

 1 Grilled Cheese

SandwhichSlide3

Grilled Cheese Example Continued

If you had 6 pieces of bread, 4 pieces of cheese, and 3 pats of butter, which of the ingredients would limit how many sandwiches could be made?

The cheese. 6 Bread could make 3 sandwiches, 3 butters could make 3 sandwiches, but 4 cheese can only make 2 sandwiches.

Which of the ingredients would be leftover?

Bread and ButterSlide4

Limiting and Excess Reagent

Limiting Reagent: reactant that determines the amount of product that can be formed

The reaction only occurs until the limiting reagent is used up (in our example, that was the cheese

)

Excess Reagent: the reactant that is not completely used up

Some of the reactant is leftover after the reaction occurs (in our example, this was the bread and butter)Slide5

How to solve limiting and excess reagent problems

You will be given 2 starting points, so you will solve 2

stoichiometry

problems.

Example:

Copper

reacts with sulfur to form copper(I) sulfide. Identify the limiting and excess reagents when 80.0 g Cu reacts with 25.0 g S.

Cu

+ S

 Cu

2

SSlide6

Practice

Problem

For each problem, indicate the limiting reagent, the excess reagent, and the amount produced.

1. The combustion of

ethene

is described below:

C

2

H

4

+ 3O

2

 2CO

2

+ 2H

2

O

If 2.70 mol C

2

H

4

is reacted with 6.30 mol O

2

, identify the limiting reagent. Slide7

Another Practice Problem

2. When 6.00 g

HCl

reacts with 5.00 g Mg, how many grams of hydrogen gas can be produced?

2HCl + Mg

 MgCl

2

+ H

2Slide8

Percent Yield

Theoretical Yield = what you could get according to

stoichiometry

Actual Yield = what is really made in the lab (usually lower than theoretical due to error/loss of efficiency in system)

Percent Yield = Actual Yield/Theoretical Yield (100)Slide9

To Solve Percent Yield Problems

Calculate the theoretical yield

Will require a stoichiometry problem

May be a limiting reagent problem (aka: 2 or more stoichiometry problems)

Find the actual yield (given to you in the problem, or found during lab)

Divide the actual yield by the theoretical yield

Multiply by 100 (it’s a percentage!)Slide10

Example Problem

If in the following reaction 0.112 g H

2

produces 0.745 g of water, what is the percent yield?

Fe

3

O

4

+ H

2

 Fe + H

2

OSlide11

Different Type of Percent Yield Problem

Sometimes, you’ll know the percent yield and need to work backwards to figure out actual yield, for example:

If the reaction of 91.3 g C

3

H

6

produces an 81.3% yield, how many grams of CO

2

would be produced?

C

3

H

6

+ O

2

 CO

2

+ H

2

O