/
10/24/2013 10/24/2013

10/24/2013 - PowerPoint Presentation

kittie-lecroy
kittie-lecroy . @kittie-lecroy
Follow
426 views
Uploaded On 2015-09-22

10/24/2013 - PPT Presentation

PHY 113 C Fall 2013 Lecture 17 1 PHY 113 C General Physics I 11 AM 1215 PM TR Olin 101 Plan for Lecture 17 Review of Chapters 913 1516 Comment on exam and advice for preparation ID: 136640

lecture 2013 113 phy 2013 lecture phy 113 fall momentum mass wave motion rope angular webassign gravitational force point

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "10/24/2013" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

1

PHY 113 C General Physics I

11 AM – 12:15 PM TR Olin 101

Plan for Lecture 17:

Review of Chapters 9-13, 15-16

Comment on exam and advice for preparation

Review

Example problemsSlide2

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

2Slide3

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

3

Webassign

questions – Assignment #15

Consider the sinusoidal wave of the figure below with the wave function

y

= 0.150 cos(15.7x − 50.3

t

)

where

x

and y are in meters and t is in seconds. At a certain instant, let point A be at the origin and point B be the closest point to A along the x axis where the wave is 43.0° out of phase with A. What is the coordinate of B? Slide4

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

4

Webassign

questions – Assignment #15

A transverse wave on a string is described by the following wave function.

y

= 0.115 sin ((π/9)

x

+

5

πt)where x and y are in meters and t is in seconds. Determine the transverse speed at t = 0.150 s for an element of the string located at x = 1.50 m.(b) Determine the transverse acceleration at

t = 0.150 s for an element of the string located at x = 1.50 m.Slide5

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

5

Webassign

questions – Assignment #15

A sinusoidal wave in a rope is described by the wave function

y = 0.20 sin (0.69

πx

+ 20

πt

)

where x and y are in meters and t is in seconds. The rope has a linear mass density of 0.230 kg/m. The tension in the rope is provided by an arrangement like the one illustrated in the figure below. What is the mass of the suspended object?

T

mgSlide6

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

6

Comment about exam on Tuesday 10/29/2013Slide7

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

7

iclicker

question

What is the purpose of exams?

Pure pain and suffering for all involved.

To measure what has been learned.

To help students learn the material.

Other.Slide8

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

8

Advice on how to prepare for the exam

Review lecture notes and text chapters 9-13,15-16

Prepare equation sheet

Work practice problems

Topics covered

Linear momentum

Rotational motion and angular momentum

Gravitational force and circular orbits

Static equilibrium

Simple harmonic motion

Wave motionSlide9

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

9

What to bring to exam:

Clear head

Calculator

Equation sheet

Pencil or penSlide10

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

10

iclicker

question:

Have you looked at last year’s exams?

A. Yes B. NoSlide11

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

11

Linear momentum

What is it?

When is it “conserved”?

Conservation of momentum in analysis of collisions

Notion of center of mass Slide12

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

12

Linear momentum -- continued

Physics of composite systemsSlide13

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

13

Example – completely

inelastic

collision; balls moving in one dimension on a frictionless surfaceSlide14

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

14

Examples of two-dimensional collision;

balls

moving on a frictionless surfaceSlide15

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

15

The notion of the center of mass and the physics of composite systemsSlide16

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

16

Finding the center of massSlide17

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

17

Rotational motion and angular momentum

Angular variables

Newton’s law for angular motion

Rotational energy

Moment of inertia

Angular momentum

qSlide18

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

18

Review of rotational energy associated with a rigid bodySlide19

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

19

Moment of inertia:Slide20

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

20

CM

CMSlide21

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

21

iclicker

exercise:

Three round balls, each having a mass M and radius R, start from rest at the top of the incline. After they are released, they roll without slipping down the incline. Which ball will reach the bottom first?

A

B

CSlide22

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

22

How

can you make

objects

rotate?

Define torque:

t

=

r

x F t = rF sin q

r

F

q

q

F

sin

qSlide23

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

23

Example form

Webassign

#11

X

t

1

t

3

t

2

iclicker

exercise

When the pivot point is O, which torque is zero?

A.

t

1

?

B.

t

2

?

C.

t

3

?Slide24

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

24

Vector cross product; right hand ruleSlide25

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

25

From Newton’s second law – continued – conservation of angular momentum:Slide26

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

26

Example of conservation of angular momentumSlide27

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

27

Summary – conservation laws we have studied so far

Conserved quantity

Necessary condition

Linear momentum

p

F

net

= 0

Angular momentum Ltnet = 0Mechanical energy E

No dissipative forcesSlide28

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

28

Fundamental gravitational force law and planetary motion

Newton’s gravitational force law

Gravity at Earth’s surface

Circular orbits of gravitational bodies

Energy associated with gravitation and orbital motionSlide29

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

29

Universal law of gravitation

 Newton (with help from Galileo,

Kepler

, etc.) 1687Slide30

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

30

Gravitational force of the Earth

R

E

m

Note: Earth’s gravity acts as a point mass located at the Earth’s center.Slide31

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

31

Stable circular orbit of two gravitationally attracted objects (such as the moon and the Earth)

R

EM

F

a

vSlide32

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

32

m

1

R

2

R

1

m

2

v

1

v

2

Circular orbital motion about center of mass

CMSlide33

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

33

m

1

R

2

R

1

m

2

v

1

v

2

L

1

=m

1

v

1

R

1

L

2

=m

2

v

2

R

2

L = L

1

+ L

2

Note: More generally, stable orbits can be elliptical.Slide34

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

34

Gravitational potential energy

Example:Slide35

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

35

Analysis of static equilibrium

Meanwhile – back on the surface of the Earth:

Conditions for stable equilibriumSlide36

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

36Slide37

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

37

T

Mg

mg

**

XSlide38

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

38

Some practice problemsSlide39

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

39Slide40

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

40

From

webassign

:

A 100-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.800 rev/s in 2.00 s? (State the magnitude of the force.)

F

R

view from top:Slide41

10/24/2013

PHY 113 C Fall 2013 -- Lecture 17

41

From

webassign

:

A 10.3-kg monkey climbs a uniform ladder with weight 

w = 1.24  102 N and length 

L

 = 3.35 m as shown in the figure below. The ladder rests against the wall and makes an angle of 

θ

 = 60.0° with the ground. The upper and lower ends of the ladder rest on frictionless surfaces. The lower end is connected to the wall by a horizontal rope that is frayed and can support a maximum tension of only 80.0 N.