Which of the following can be the final product of an expressed gene mRNA tRNA rRNA polypeptide Which of the following can be the final product of an expressed gene mRNA tRNA rRNA polypeptide ID: 553460
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Slide1
Gene Expression: From Gene to ProteinSlide2
Which of the following can be the final product of an expressed gene?
mRNA
tRNArRNApolypeptideSlide3
Which of the following can be the final product of an expressed gene?
mRNA
tRNArRNA
polypeptideSlide4
Which of the following terms does not pertain to translation?
anticodon
tRNAaminoacyl-tRNA
synthetase
polypeptide
rRNA
DNASlide5
Which of the following terms does not pertain to translation?
a
nticodontRNA
aminoacyl-tRNA
synthetase
polypeptide
rRNA
DNASlide6
The template strand of a given gene includes the sequence 3
-G C C A C G T A T C A G-5
What is the sequence of the
nontemplate
strand?
3
-C G
G
T G C A T A G T-5
5
-C G G T G C A T A G T-35-C G G U G C A U G U-33-C G G U G C A U G U-5Slide7
The template strand of a given gene includes the sequence 3
-G C C A C G T A T C A G-5
What is the sequence of the
nontemplate
strand?
3
-C G
G
T G C A T A G T-5
5
-C G G T G C A T A G T-35-C G G U G C A U G U-33-C G G U G C A U G U-5Slide8
Which of the following is the best example of gene expression?
A frog adapts to variation in its environmental temperature.
Mouse fur color results from pigment formed by gene-encoded enzymes.DNA is replicated during the S phase of the cell cycle.
The percent of A versus a alleles in a population is altered by natural selection.
Mutation alters the sequence of a region of DNA.Slide9
Which of the following is the best example of gene expression?
A frog adapts to variation in its environmental temperature.
Mouse fur color results from pigment formed by gene-encoded enzymes.DNA is replicated during the S phase of the cell cycle.
The percent of A versus a alleles in a population is altered by natural selection.
Mutation alters the sequence of a region of DNA.Slide10
The ability of genes from one species to be expressed in a different species is possible because of which property of the genetic code?
the near universality of the genetic code
All species in E
ukarya
use the same genetic code.
Gene expression
doesn
’
t utilize the genetic code.RNA codons are the same in all organisms, but
DNA codons are different.
Gene expression in the
laboratory is tolerant of
genetic differences.Slide11
The ability of genes from one species to be expressed in a different species is possible because of which property of the genetic code?
the near universality of the genetic code
All species in Eukarya
use the same genetic code.
Gene expression
doesn
’
t utilize the genetic code.
RNA codons are the same in all organisms, but
DNA codons are different.
Gene expression in the
laboratory is tolerant of
genetic differences.Slide12
In the transcription process, as diagrammed in Figure 17.7 and below, in which process (1, 2, or 3) does the RNA polymerase bind to the promoter, is the RNA transcript released, and is the RNA transcript extended?
1; 2; 3
2; 3; 1
3; 2; 1
1; 3; 2Slide13
In the transcription process, as diagrammed in Figure 17.7 and below, in which process (1, 2, or 3) does the RNA polymerase bind to the promoter, is the RNA transcript released, and is the RNA transcript extended?
1; 2; 3
2; 3; 1
3; 2; 1
1; 3; 2Slide14
Which of the following components
doesn
’t form part of the transcription complex at a eukaryotic promoter?
TATA box
start point
transfer RNA
transcription factors
RNA polymeraseSlide15
Which of the following components
doesn
’t form part of the transcription complex at a eukaryotic promoter?
TATA box
start point
transfer RNA
transcription factors
RNA polymeraseSlide16
Which of the following is not a modification made to eukaryotic mRNA before it goes to the cytosol?
The 5
end is capped
A poly-A tail is added to the 3
end
Introns are removed
Exons are joined together
Spliceosomes
are removedSlide17
Which of the following is not a modification made to eukaryotic mRNA before it goes to the cytosol?
The 5
end is capped
A poly-A tail is added to the 3
end
Introns are removed
Exons are joined together
Spliceosomes
are removedSlide18
Which of the following is not a difference between prokaryotic and eukaryotic transcription?
Part
of the RNA polymerase specifically recognizes and binds to the promoter in bacteria; in
eukaryotes,
transcription factors mediate the binding of
polymerase.
The
RNA transcript is immediately useable as mRNA;
in eukaryotes, the
RNA transcript is
processed.
RNA
polymerase
requires
a primer in bacteria; in
eukaryotes,
it does
not.
Eukaryotic
transcription has a
polyadenylation
signal sequence; in
prokaryotes,
a transcription terminator causes the polymerase to detach
and
release the
transcript.Slide19
Which of the following is not a difference between prokaryotic and eukaryotic transcription?
Part
of the RNA polymerase specifically recognizes and binds to the promoter in bacteria; in
eukaryotes,
transcription factors mediate the binding of
polymerase.
The
RNA transcript is immediately useable as mRNA;
in eukaryotes,
the RNA transcript is
processed.
RNA
polymerase
requires
a primer in bacteria; in
eukaryotes,
it does
not.
Eukaryotic
transcription has a
polyadenylation
signal sequence; in
prokaryotes,
a transcription terminator causes the polymerase to detach and release the
transcript.Slide20
Which of the following is incorrectly identified in the figure (Figure 17.15)?
5
and 3
ends
hydrogen bond
amino acid attachment site
anticodon loop
A
B
D
CSlide21
Which of the following is incorrectly identified in the figure (Figure 17.15)?
5
and 3
ends
hydrogen bond
amino acid attachment site
anticodon loop
A
B
D
CSlide22
Aminoacyl-tRNA
synthetase is an enzyme whose function is to ________.link a
tRNA
to its amino acid
r
emove introns from a pre-RNA transcript
c
ause the RNA polymerase to detach from the DNAjoin together RNA nucleotides complementary to the DNA template stran
dSlide23
Aminoacyl-tRNA
synthetase is an enzyme whose function is to ________.link a
tRNA
to its amino acid
r
emove introns from a pre-RNA transcript
Cause the RNA polymerase to detach from the DNA
join together RNA nucleotides complementary to the DNA template strandSlide24
To show how sequence logos are made, the potential ribosome-binding regions from
10
Escherichia
coli
genes are shown in a sequence alignment. The figure to the right is the sequence logo derived from the aligned sequences. In the sequence logo, the horizontal axis shows the primary sequence of the DNA by nucleotide position. Letters for each base are stacked on top of each other according to their relative frequency at that position among the aligned sequences, with the most common base as the largest letter at the top of the stack. The height of each letter represents the relative frequency of that base at that position
.
Scientific Skills ExerciseSlide25
In the sequence alignment (on the previous slide), how many of each base appear at position –9?
5 G, 4 A, 1 T, 0 C
7 G, 2 A, 1 C, 0 T4 G, 3 T, 3 A, 0 CSlide26
In the sequence alignment (on the previous slide), how many of each base appear at position –9?
5 G, 4 A, 1 T, 0 C
7 G, 2 A, 1 C, 0 T4 G, 3 T, 3 A, 0 CSlide27
In the sequence alignment,
how many of each base appear at position 0
? 8
A, 1 G, 1 T, 0 C
4
T, 3 C, 3 A, 0 G
10
T, 0 A, 0 C, 0
GSlide28
In the sequence alignment,
how many of each base appear at
position 0? 8 A, 1 G, 1 T, 0 C
4
T, 3 C, 3 A, 0 G
10
T, 0 A, 0 C, 0
GSlide29
In the sequence alignment, how many of each base appear at position 1
?
10 G, 0 C, 0 A, 0 T4 T, 3 C, 3 A, and 0 G10 T, 0 A, 0 C, 0 GSlide30
In the sequence alignment, how many of each base appear at position 1?
10 G, 0 C, 0 A, 0 T
4 T, 3 C, 3 A, and 0 G10 T, 0 A, 0 C, 0 GSlide31
The height of a stack of letters in a logo indicates the predictive power of that stack (determined statistically). If the stack is tall, we can be more confident in predicting what base will be in that position if a new sequence is added to the logo. For example, at position 2, all 10 sequences have a G; the probability of finding a G there in a new sequence is very high, as is the stack. For short stacks, the bases all have about the same frequency, so it’s hard to predict a base at those positions.
Which two positions in the logo sequence have the
most
predictable bases, and which bases would you predict at those two positions in a newly sequenced gene
?
position
1 (T) and position 2 (G)
position
–10 (G) and position –7 (A)
position
0 (A) and position 2 (G)
position
0 (A) and position 1 (T
)Slide32
The height of a stack of letters in a logo indicates the predictive power of that stack (determined statistically). If the stack is tall, we can be more confident in predicting what base will be in that position if a new sequence is added to the logo. For example, at position 2, all 10 sequences have a G; the probability of finding a G there in a new sequence is very high, as is the stack. For short stacks, the bases all have about the same frequency, so it’s hard to predict a base at those positions.
Which two positions in the logo sequence have the
most
predictable bases, and which bases would you predict at those two positions in a newly sequenced gene
?
position
1 (T) and position 2 (G)
position
–10 (G) and position –7 (A)
position
0 (A) and position 2 (G)
position
0 (A) and position 1 (T
)Slide33
Which positions in the logo have the
least
predictable bases? How can you tell?All positions other than 1 and 2 have equally low predictive power because they have multiple bases in their stacks.
The four positions with the shortest stacks of bases have the lowest predictive power (–15, –14, –3, and 3).
The 13 positions that are each missing at least one base from the stack have the lowest predictive power
(–15, –13, –9, –8, –7, –3, –1, 0, 1, 2, 3, 4, and 7).
The 12 positions showing no bases have the lowest predictive power (–18, –17, –16, –12, –11, –6, –5, –4,
–2, 5, 6, and 8).Slide34
Which positions in the logo have the
least
predictable bases? How can you tell?All positions other than 1 and 2 have equally low predictive power because they have multiple bases in their stacks.
The four positions with the shortest stacks of bases have the lowest predictive power (–15, –14, –3, and 3).
The 13 positions that are each missing at least one base from the stack have the lowest predictive power
(–15, –13, –9, –8, –7, –3, –1, 0, 1, 2, 3, 4, and 7).
The 12 positions showing no bases have the lowest predictive power (–18, –17, –16, –12, –11, –6, –5, –4,
–2, 5, 6, and 8).Slide35
In the actual experiment, the researchers used 149 sequences to build their sequence logo, as opposed to just 10. Now there is a stack at each position, however short, because the sequence logo includes more data.Slide36
Which three positions in the sequence logo in the figure have the
most
predictable bases? Name the most frequent base at each position.position –18 (T); position –5 (A); position 8 (A)
position 0 (A); position 1 (T); position 2 (G)
position 0 (T); position 1 (A); position 2 (C)
position –11 (G); position –10 (G); position –9 (G)Slide37
Which three positions in the sequence logo in the figure have the
most
predictable bases? Name the most frequent base at each position.position –18 (T); position –5 (A); position 8 (A)
position 0 (A); position 1 (T); position 2 (G)
position 0 (T); position 1 (A); position 2 (C)
position –11 (G); position –10 (G); position –9 (G)Slide38
What gene feature is represented by the bases in positions 0–2?
the translation stop codon
the transcription start site ATG
the ribosome binding site
the translation start codon AUGSlide39
What gene feature is represented by the bases in positions 0–2?
the translation stop codon
the transcription start site ATG
the ribosome binding site
the translation start codon AUGSlide40
Based on the logo, what five adjacent base positions in the 5' UTR region (the untranslated region at the 5' end of the mRNA) are most likely involved in ribosome binding?
Positions –1 to 3 include the tallest stacks; therefore, they represent the most likely sequence for the ribosome binding site.
Positions –12 to –8 have the tallest stacks in the 5' UTR region; therefore, they represent the most likely sequence
for the ribosome binding site.
Positions –5 to –1 are adjacent to
the AUG start codon in the 5' UTR
region; therefore, they represent
the most likely sequence for the
ribosome binding site.Slide41
Based on the logo, what five adjacent base positions in the 5' UTR region (the untranslated region at the 5' end of the mRNA) are most likely involved in ribosome binding?
Positions –1 to 3 include the tallest stacks; therefore, they represent the most likely sequence for the ribosome binding site.
Positions –12 to –8 have the tallest stacks in the 5' UTR region; therefore, they represent the most likely sequence
for the ribosome binding site.
Positions –5 to –1 are adjacent to
the AUG start codon in the 5' UTR
region; therefore, they represent
the most likely sequence for the
ribosome binding site.