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11.1 Measures of Center and Variation 11.1 Measures of Center and Variation

11.1 Measures of Center and Variation - PowerPoint Presentation

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Uploaded On 2018-12-05

11.1 Measures of Center and Variation - PPT Presentation

What We Will Learn Compare mean median and mode Find range and standard deviation Identify effects of transformations on data Needed Vocab Measure of center mean median and mode Mean sum of the data divided by total number of data values aka average ID: 735949

median data deviation mode data median mode deviation find values standard range measures outlier number center set measure step

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Presentation Transcript

Slide1

11.1 Measures of Center and VariationSlide2

What We Will Learn

Compare mean, median, and mode

Find range and standard deviation

Identify effects of transformations on dataSlide3

Needed Vocab

Measure of center:

mean, median, and mode

Mean:

sum of the data divided by total number of data values, aka average

Median:

middle number when values written in order

Mode:

value or values that occur the most

Outlier

: data value much larger or smaller than the other values

Measure of variation:

describes the spread or distribution

Range:

difference of greatest value and least value

Standard deviation:

how much a value in the data set differs from the mean

Data transformation:

use a mathematical operation to change a data set into different data setSlide4

Ex. 1 Comparing Measures of Center

Aka Measures of Central Tendency

A. Find mean, median, and mode

B. Which measure best represents the data?

Mean = 9.65

Median

=

8.7

Remember to write in numerical value to find median, if even number the add middle two and divide by 2Mode = 8.25Median - as mean bigger than most data values, and modes less than most data values

Hourly

Wages

16.50

8.25

8.75

8.45

8.65

8.25

9.10

9.25Slide5

Ex. 2 Removing an Outlier

How does outlier affect the mean, median, and mode?

Run mean, median, and mode with outlier and then run without and see difference

With outlier mean = 9.65, median = 8.7 and mode = 8.25

Without mean = 8.67, median = 8.65, and mode is 8.25

Hourly

Wages

16.50

8.25

8.75

8.45

8.65

8.259.109.25

Mean decreased by .98, median decreased by .05, and mode stayed the sameSlide6

Ex. 3 Finding Range

Simply subtract highest and lowest data value

What is the range of contestants on show A?

31 – 19

12 yearsSlide7

Ex. 4 Finding Standard Deviation

Find standard deviation of the ages in show B.

Use

Can make a table if you want, easier to see for some people

 

Steps

1. find the mean of the data

2. find deviation by taking data value and subtracting the mean found in step 1

3. square each deviation found in step 2

4. add all the squared deviations and then divide by total items

5. take square root of answer from step 4Slide8

Ex. 4 Continued

55.8

7.5 years

 

x

25

20

22

27

48

32

19

27

25

22

21

24

mean

26

26

26

26

26

26

26

2626262626

x-mean-1-6-41226-71-1-4-5-2

squared

1

36

16

1

484

36

49

1

1

16

25

4Slide9

Your Practice

Find standard deviation

Page 591 number 22

6.7575

2.6

 Slide10

Ex. 5 Effects of Data TransformationsSlide11

Ex. 5 Continued

Find the values of the measures shown when each value is increased by 14. Find the values of the measures when values multiplied by 1.2.

Mean = 62, median = 56, mode = 49, range = 46, standard deviation = 15.5

Increased by 14:

Mean = 76, median = 70, mode = 63, range = 46, standard deviation = 15.5

Multiplied by 1.2:

Mean = 74.4, median = 84, mode = 75.6, range = 55.2, standard deviation = 18.6